Answer:
i......dont........know.... :)
Step-by-step explanation:
yup
Supposing that the integers are x, y and z, and that their average is 8, then
x+y+z
-------- = 8, or x + y + z = 24.
3
Let's experiment. Making up a table, we get:
x y z sum (sum MUST be 24)
5 9 10 24
4 9 11 24
3 10 11 24
2 11 11 24
1 11 12 24
1 10 13 24
1 1 22 24
Can't choose integers smaller than 1, so it appears that 22 is the largest possible integer that could be one of x, y and z.
Answer:
8/1.50 = 128/x
Step-by-step explanation:
In this case, I put the amount of fruit drink over the cost!
8 ounces/$1.50
there are 128 ounces in a gallon and we want to find out the cost of a gallon, so we can put that as x!
128 ounces/x
There's your proportion! Hope this helps :)
Answer:
A) y^3+27
Step-by-step explanation:
There are two ways of solving this problem:
1. Recognizing this as the factored form of the sum of perfect cubes
2. Distribute and add the like terms.
1. In order to distribute we must multiply y by y^2-3y+9, and then 3 by y^2-3y+9:


After we add the positive and negative 3y^2 and 9y, they will cancel out and be gone entirely:

2. You know how you can factor the difference of perfect squares?
As an example:

Well, not many people know this but you can actually factor both the sum and difference of perfect cubes:


Because we have these identities, we can easily establish here that we have the sum of perfect cubes, and that (y+3)(y^2-3y+9)= y^3+3^3 = y^3+27