Answer:
Bo teaches 20 classes per week.
Erica teaches 28 classes per week.
Step-by-step explanation:
Let x= yoga classes taught by Bo
and y=yoga classes taught by Erica
We get the following system of equations
x+y=48 (equation 1)
y=2x-12 (equation 2)
Solve the system of equation:
Using equation 1:
x=48-y
Substitute x in equation 2:
y=2(48-y)-12
=96 - 2y - 12
2y+y=84
3y=84
y=84/3 =28
Substitute in equation 1:
x+28=48
x=48-28=20
So Bo teaches 20 classes per week and Erica teaches 28 classes per week.
Hope this helps :)
Find the difference between the two years then divide that by the first year amount.
42,365 - 40,006 = 2,359
2,359 / 40,006 = 0.0589
Multiply by 100 to get the percent:
0.0589 x 100 = 5.89%
Rounded to nearest whole percent = 6%
Answer 6%
Well, if the selling price was 210, and that's the 100%, then if he adds 60% to that, the new price will be 160% of 210... well, if 210 is the 100%, what's 160% of that?
solve for "x".
Answer:Jarvis's class average is 75
Step-by-step explanation:
The total possible average score for the math course is 100
a) If the teacher rates homework at 10%, it means that the total possible score for homework
is 10/100 × 100 = 10
If his homework average is 93, then his score would be
(93×10)/100 = 9.3
b) If the teacher rates quizzes at 30%, it means that the total possible score for quizzes
is 30/100 × 100 = 30
If his quiz average is 82, then his score would be
(82×30)/100 = 24.6
c) If the teacher rates test at 40%, it means that the total possible score for quizzes
is 40/100 × 100 = 40
If his quiz average is 72, then his score would be
(72×40)/100 = 28.8
d) If the teacher rates final exam at 20%, it means that the total possible score for quizzes
is 20/100 × 100 = 20
If his final exam is 60, then his score would be
(60×20)/100 = 12
Jarvis's class average would be
9.3 + 24.6 + 28.8 + 12 = 74.7
Approximately 75
SOLUTION:
<h2>
Explanation:</h2>
Let's use the following System of Linear Equations in Two Variables in order to solve this exercise:
So we can graph these lines using two points.
For eq (1):
So graph a line that passes through these two points. This is the red line shown below.
For eq (2):
So graph a line that passes through these two points. This is the blue line shown below.
<em>The solution of this system of equation is the point of intersection, which is (1,3)</em>
<h2>Learn more:</h2>
Parallel lines: brainly.com/question/12169569
#LearnWithBrainly
