Let
x---------> radius of the cylinder
y---------> the height of the cylinder
we know that
x=2y
[surface area of cylinder]=2*[pi*r²]+2*pi*r*h
surface area=108*pi m²
r=x
h=y
x=2y
108*pi=2*[pi*(2y)²]+2*pi*(2y)*y
108*pi=8*pi*y²+4*pi*y²
108*pi=12*pi*y²
y²=108/12
y²=9----------> y=√9--------> y=3 m
x=2y-------> x=2*3-----> x=6 m
the answer is
the height of the cylinder is 3 m
Answer: Answer is 3
BC 6
------ = ------
XY 3
Step-by-step explanation:
The statements below can be used to prove that the triangles are similar.
On a coordinate plane, right triangles A B C and X Y Z are shown. Y Z is 3 units long and B C is 6 units long.
A B Over X Y = 4 Over 2
?
A C Over X Z = 52 Over 13
△ABC ~ △XYZ by the SSS similarity theorem.
Which mathematical statement is missing?
1. Y Z Over B C = 6 Over 3
2. ∠B ≅ ∠Y
3. B C Over Y Z = 6 Over 3
4. ∠B ≅ ∠Z
<span><span>3/5(50)
=(3/5)(50/1)
=(3)(50)/(5)(1)
=150/5
=30 </span></span>
5×4=20 , 12×4=48
53÷4 = 13 then
x=13
Answer:
72w+36
Step-by-step explanation: