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2 years ago

10

Combine the like terms

2 answers:

Nonamiya [84]2 years ago

7 0

19.) 10u+4
20.) -6x-4x^3-11-2x^2

Aleksandr-060686 [28]2 years ago

4 0

The answer for:

20)
6x-7+6x³-4x-10x³-4-8x - 2x²= −43−22−6−11

19)
8u+6+7u+(-10) + (-5u) + 8= 10+4

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2 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

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3 years ago

How to find the Perimeter?

SOVA2 [1]

Answer:

8+2 $\sqrt{20\\}\\$

Step-by-step explanation:

2+2+2+2+ $\sqrt{20\\}\\$ + $\sqrt{20\\}\\$ =8+2 $\sqrt{20\\}\\$

4^2+2^2=h^2

20=h^2

h= $\sqrt{20\\}\\$

7 0

3 years ago