Does anyone know how to do the work these out? thank you!! ☺️

Mathematics

1 answer:

notsponge [240]3 years ago

4 0

I figured it out but I can’t show the picture but I know the answer it’s D

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Write the expression 12^-2 in simplest form.

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Step-by-step explanation:

1/12^2 = 1/144

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6×2p to the second power when p=5

geniusboy [140]

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3600

Step-by-step explanation:

Since the question gives you p, you replace p (which is just a placeholder) with 5.

Your equation should look like this:

$(6*2(5))^2 = 3600$

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For number 6, evaluate the definite integral.

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$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
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$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
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u(0)=8+2(0)\implies u(0)=8
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u(28)=8+2(28)\implies u(28)=64$

$\bf \\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
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\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2} \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3$

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There’s not enough information to answer your question.

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3 years ago

Gym A charges $9.00 per hour of childcare. Gym B charges $0.75 per 5 minutes of childcare.

TEA [102]

Answer:

$9.00

Step-by-step explanation:

0.75 times 12 equals 9

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4 years ago

Read 2 more answers