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kumpel [21]
3 years ago
14

I kinda need help. Math isn't my best subject.

Mathematics
1 answer:
Brrunno [24]3 years ago
8 0
She earn $55,200

92,000 * .6 =
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Someone please help I’ll mark as brainliest
Naya [18.7K]

Answer:

5

Step-by-step explanation:

because when you subtract the biggest (6) number by the smallest (1) and you subtract them you get 5

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3 years ago
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4. Find each quotient. a.18/-3 b.-5/-1 c.24/-6 d.-10/-1 e.-25/5 f.8/-2
Nataly_w [17]

Answer:

Step-by-step explanation:

a.18/-3  = (-6)

b.  -5/-1 = 5

c. 24/-6 = (-4)

d. -10/-1  = 10

e. -25/5 =(-5)

f.    8/-2 = (-4)

In multiplication and division, if there are are odd number of negative signs, the result will have negative sign.

If there are even number of negative signs, the the result will have positive sign

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2 years ago
HELLLLLP MEHHHHHHHH PLSSSSSSS
Wewaii [24]

Answer:

They both have the same range

Step-by-step explanation:

375-175=200

400-200=200

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2 years ago
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50 written as a product of its prime fac<br> tors
Maru [420]
Start by identifying any factor of 50 and then rewriting 50 to include that one factor and another:

50 = 5 * 10              5 is prime, but 10 is not.  Thus, factor 10:

50 = 5 * 5 * 2        This is 50 as a product of its prime factors 5, 5 and 2.
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3 years ago
The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc
BaLLatris [955]

Answer:

y(t)= 6-3cos(\dfrac{2\pi}{14}t )

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

y(t) = y_0+Acos(wt)

The tide varies between 3ft and 9ft, which means its amplitude A is

A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}

and its midline y_0 is

y_o=3+3 \\\\\boxed{y_o= 6ft}.

Furthermore, since at t=0 the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is -cos(\omega t).

The period of the full cycle is 14 hours, which means

\omega t =2\pi

\omega (t+14)= 4\pi

giving us

\boxed{\omega = \dfrac{2\pi}{14}.}

With all of the values of the variables in place, the function modeling the situation now becomes

\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}

8 0
3 years ago
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