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attashe74 [19]
2 years ago
14

What does "employable" mean and how does it relate to careers?

Business
1 answer:
ipn [44]2 years ago
7 0

Answer:

employablee means that your able to apply to get a job i think but im not sure i just need these points lol

Explanation:

You might be interested in
Destin Company uses the weighted average method in its process costing system. The first processing department, the welding depa
ICE Princess25 [194]

Answer:

the cost per equivalent unit for conversion costs for the month is $ 6.256 (round off to three decimal places)

Explanation:

The Concept of Equivalent units measures the number of units of output in terms of percentage completion of a certain input element.

In this question we  are required to find the cost per equivalent unit for conversion costs.

Step 1 Find the Total conversion costs for the period.

Conversion cost in this beginning work in process inventory $19,200

Conversion costs incurred in the  during the month              $383,060

Total conversion costs for the period                                      $402,260

Step 2 Find the Total Equivalent units

Hint : First find the Units Completed

Units Completed = 10000+6000-19000

                            =  51,000

<u> Total Equivalent units</u>

Units Completed (  51,000 × 100 %)                  = 51,000

Closing Work In progress (  19,000 × 70 %)      =13,300

Total Equivalent units                                         =64,300

Step 3 Find cost per equivalent unit for conversion costs

cost per equivalent unit = Total conversion costs / Total Equivalent units

                                          =  $402,260 / 64,300

                                          =  $ 6.256 (round off to three decimal places)

3 0
3 years ago
An improvement in a country's balance of payments means a decrease in its balance of payments deficit, or an increase in its sur
FrozenT [24]

Answer:

Should be D (sometimes harmful).

7 0
3 years ago
When the demand for the economy is expanding, the demand for loanable funds will ________.
nikklg [1K]

When the demand for the economy exist expanding, the demand for loanable funds will increase.

<h3>What is Demand?</h3>

The quantity of a good that consumers are willing and able to buy at various prices at a specific time period and location is known as the demand. The demand curve is another name for the relationship between price and quantity demand. Demand is just a consumer's desire to buy products and services immediately and to pay the price associated with them. Demand can be defined as the quantity of things that consumers are prepared and willing to purchase at various prices within a specific time frame.

Loanable funds are all the resources that individuals and organizations in a given economy have chosen to set aside and lend to investors rather than use for their own needs. Savings are the source of the loanable funds available. It is predicated on borrowing that loanable funds are in demand. The real interest rate and the amount of loans made depend on how the supply of savings and the demand for loans interact.

Hence, When the demand for the economy exist expanding, the demand for loanable funds will increase.

To learn more about Demand refer to:

brainly.com/question/1245771

#SPJ4

7 0
1 year ago
Suppose that output (Y ) in an economy is given by the following aggregate production function: Yt = Kt + Nt where Kt is capital
shusha [124]

Answer:

Check the explanation

Explanation:

Yt = Kt + Nt

Taking output per worker, we divide by Nt

Yt/Nt = Kt/Nt + 1

yt = kt + 1

where yt is output per worker and kt is capital per worker.

a) With population being constant, savings rate s and depreciation rate δ.

ΔKt = It - δKt

dividing by Nt, we get

ΔKt/Nt = It/Nt - δKt/Nt ..... [1]

for kt = Kt/Nt, taking derivative

d(kt)/dt = d(Kt/Nt)/dt ... since Nt is a constant, we have

d(kt)/dt = d(Kt/Nt)/dt = (dKt/dt)/Nt = ΔKt/Nt = It/Nt - δKt/Nt = it - δkt

thus, Capital accumulation Δkt = i – δkt

In steady state, Δkt = 0

That is I – δkt = 0

S = I means that I = s.yt

Thus, s.yt – δkt = 0

Then kt* = s/δ(yt) = s(kt+1)/(δ )

kt*= skt/(δ) + s/(δ)

kt* - skt*/(δ) = s/(δ)

kt*(1- s/(δ) = s/(δ)

kt*((δ - s)/(δ) = s/(δ)

kt*(δ-s)) = s

kt* = s/(δ -s)

capital per worker is given by kt*

b) with population growth rate of n,

d(kt)/dt = d(Kt/Nt)/dt =

= \frac{\frac{dKt}{dt}Nt - \frac{dNt}{dt}Kt}{N^{2}t}

= \frac{dKt/dt}{Nt} - \frac{dNt/dt}{Nt}.\frac{Kt}{Nt}

= ΔKt/Nt - n.kt

because (dNt/dt)/Nt = growth rate of population = n and Kt/Nt = kt (capital per worker)

so, d(kt)/dt = ΔKt/Nt - n.kt

Δkt = ΔKt/Nt - n.kt = It/Nt - δKt/Nt - n.kt ......(from [1])

Δkt = it - δkt - n.kt

at steady state Δkt = it - δkt - n.kt = 0

s.yt - (δ + n)kt = 0........... since it = s.yt

kt* = s.yt/(δ + n) =s(kt+1)/(δ + n)

kt*= skt/(δ + n) + s/(δ + n)

kt* - skt*/(δ + n) = s/(δ + n)

kt*(1- s/(δ + n)) = s/(δ + n)

kt*((δ + n - s)/(δ + n)) = s/(δ + n)

kt*(δ + n -s)) = s

kt* = s/(δ + n -s)

.... is the steady state level of capital per worker with population growth rate of n.

3. a) capital per worker. in steady state Δkt = 0 therefore, growth rate of kt is zero

b) output per worker, yt = kt + 1

g(yt) = g(kt) = 0

since capital per worker is not growing, output per worker also does not grow.

c)capital.

kt* = s/(δ + n -s)

Kt*/Nt = s/(δ + n -s)

Kt* = sNt/(δ + n -s)

taking derivative with respect to t.

d(Kt*)/dt = s/(δ + n -s). dNt/dt

(dNt/dt)/N =n (population growth rate)

so dNt/dt = n.Nt

d(Kt*)/dt = s/(δ + n -s).n.Nt

dividing by Kt*

(d(Kt*)/dt)/Kt* = s/(δ + n -s).n.Nt/Kt* = sn/(δ + n -s). (Nt/Kt)

\frac{sn}{\delta +n-s}.\frac{Nt}{Kt}

using K/N = k

\frac{s}{\delta +n-s}.\frac{n}{kt}

plugging the value of kt*

\frac{sn}{\delta +n-s}.\frac{(\delta + n -s)}{s}

n

thus, Capital K grows at rate n

d) Yt = Kt + Nt

dYt/dt = dKt/dt + dNt/dt = s/(δ + n -s).n.Nt + n.Nt

using d(Kt*)/dt = s/(δ + n -s).n.Nt from previous part and that (dNt/dt)/N =n

dYt/dt = n.Nt(s/(δ + n -s) + 1) = n.Nt(s+ δ + n -s)/(δ + n -s) = n.Nt((δ + n)/(δ + n -s)

dYt/dt = n.Nt((δ + n)/(δ + n -s)

dividing by Yt

g(Yt) = n.(δ + n)/(δ + n -s).Nt/Yt

since Yt/Nt = yt

g(Yt) = n.(δ + n)/(δ + n -s) (1/yt)

at kt* = s/(δ + n -s), yt* = kt* + 1

so yt* = s/(δ + n -s) + 1 = (s + δ + n -s)/(δ + n -s) = (δ + n)/(δ + n -s)

thus, g(Yt) = n.(δ + n)/(δ + n -s) (1/yt) =  n.(δ + n)/(δ + n -s) ((δ + n -s)/(δ + n)) = n

therefore, in steady state Yt grows at rate n.

5 0
3 years ago
On January 2, 2019, Twilight Hospital purchased a $96,400 special radiology scanner from Crane Inc. The scanner had a useful lif
Aneli [31]
  • The preparation of the incremental analysis of Twilight hospital is presented below:

<u>Particulars      Retain scanner    Replace scanner    Net income </u>

Annual

operating cost   $318,000            $243,000              $75,000

             ($106,000 × 3)                                        ($25,000 × 3)

New

scanner cost                                      $110,000        -$110,000

Old scanner salvage                          -$45,500        $45,500

Total                             $318,000      $307,500      $10,500

In this way, the incremental analysis should be prepared.

Learn more about the salvage value here: brainly.com/question/15711481

4 0
3 years ago
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