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Deffense [45]
3 years ago
8

A) A semi-cylinder of negligible mass is placed on a smooth horizontal surface and

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
6 0
It’s c I just google the answer and did the test it’s c
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I need the answer pls answer fast
son4ous [18]

Answer:

A = 846 in²

Step-by-step explanation:

The area (A) of a rhombus is calculated as

A = \frac{1}{2} × d₁ × d₂ ( d₁ and d₂ are the diagonals ) , then

A = \frac{1}{2} × 36 × 47 = 18 × 47 = 846 in²

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3 years ago
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What diagram do I use???
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Answer:

A Bar Graph

Step-by-step explanation:

This would be the best choice make the x axis the sports

and the y axis the numbers and make 2 bars for each sport one for girls one for boys

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3 years ago
A yo-yo rotates 12 times every
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6 0
3 years ago
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74
lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0
3 years ago
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