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Deffense [45]
2 years ago
8

A) A semi-cylinder of negligible mass is placed on a smooth horizontal surface and

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
6 0
It’s c I just google the answer and did the test it’s c
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The following data on average daily hotel room rate and amount spent on entertainment (The Wall Street Journal, August 18, 2011)
Zielflug [23.3K]

Answer:

a. Predicted Amount = $109.46

b. Confidence Interval = (94.84,124.08)

c. Interval = (110.6883,188.8517)

Step-by-step explanation:

Given

ŷ = 17.49 + 1.0334x.

SSE = 1541.4

a.

ŷ = 17.49 + 1.0334(89)

ŷ = 109.4626

ŷ = 109.46 --- Approximated

Predicted Amount = $109.46

b.

ŷ = 17.49 + 1.0334(89)

ŷ = 109.4626

ŷ = 109.46

First we calculate the standard deviation

variance = SSE/(n-2)

v = 1541.4/(9-2)

v = 1541.4/7

v = 220.2

s = √v

s = √220.2

s = 14.839

Then we calculate mean(x) and ∑(x - (mean(x))²

X --- Y -- Mean(x) --- ∑(x - (mean(x))²

148 -- 161 -- 43-- 1849

96 || 105|| -9 || 81

91 ||101 || -14 || 196

110 || 142 || 5 || 25

90 || 100 || -15 || 225

102 || ||120 ||-3|| 9

136 || 167 ||31 ||961

90 || 140 ||-15 ||225

82 || 98 ||-23 || 529

Sum 945 || 1134|| 0 ||4100

Mean (x) = 945/9 = 105

∑(x - (mean(x))² = 4100

α = 1 - 95% = 5%

α/2 = 2.5% = 0.025

tα,df = n − 2 = t0.025,7 =2.365

Confidence interval = 109.46 ± 2.365 * 14.839 √((1/9)+ (89-105)²/4100

Confidence Interval = (109.46 ± 14.62)

Confidence Interval = (94.84,124.08)

c.

ŷ = 17.49 + 1.0334(128)

ŷ = 149.7652

ŷ = 149.77

Interval = 149.77 ± 2.365 * 14.839 √((1/9)+ (128-105)²/4100

Interval = 149.77 ± 39.0817

Interval = (110.6883,188.8517)

3 0
3 years ago
The sum of the angle measures of a quadrilateral is 360° Write and<br> 85<br> 115<br> 60
Misha Larkins [42]
The third angle would be 100 degrees
Explanation: 360-85-115-60= 100
3 0
3 years ago
n automatic machine in a manufacturing process is operating properly if the lengths of an important subcomponent are normally di
Paraphin [41]

Answer:

0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 116 cm and a standard deviation of 5.4 cm.

This means that \mu = 116, \sigma = 5.4

Find the probability that one selected subcomponent is longer than 118 cm.

This is 1 subtracted by the pvalue of Z when X = 118. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{118 - 116}{5.4}

Z = 0.37

Z = 0.37 has a pvalue of 0.6443

1 - 0.6443 = 0.3557

0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.

8 0
2 years ago
PLEASE HELP ME! Simplify the expression.
mote1985 [20]
First expression simplified would be
-2z - 63

second expression would be
-a + b

i hope that’s right!!!!!!! i’m so sorry if it’s not
8 0
2 years ago
Please help due today and please write the explanation.
joja [24]

if u have a phone use photo math to scan the equations, its very useful

6 0
3 years ago
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