Which situation represents a proportional relationship?

Express 3m24cm in kilometers,leaving your answer in standard form

erastova [34]

Answer:

0.00324 kilometres

Step-by-step explanation:

Remember:

100 centimeters = 1 meter

1000 meters = 1 kilometer

So first, let's add together the meters and centimeters. To do that, we have to convert the meters to centimeters. That would become 300 centimeters, then you add the 24 centimeters to get 324 centimeters. Then, you convert that to kilometers. You can use a calculator for this, but I'll show you how to do this without a calculator. Since 100 centimeters is one meter, and 1000 meters equals to one kilometer, there would be 5 spaces from 324 to our answer, so you move the invisible decimal point 5 spaces to the left, and you get your answer, which is 0.00324 kilometres!

7 0

3 years ago

Read 2 more answers

What is the value of k in the equation 5k-2k=12

Mamont248 [21]

Answer:

k =4

Step-by-step explanation:

5k-2k=12

Combine like terms

3k = 12

Divide each side by 3

3k/3 = 12/3

k = 4

5 0

3 years ago

Read 2 more answers

What is the benefit of using statistical sampling versus nonstatistical sampling?

taurus [48]

Statistical sampling: Uses laws of probability for selection and evaluation of a sample. Allows for quantification of audit risk and sufficiency of audit evidence. Nonstatistical sampling: Does not utilize statistical models in calcualtions. Uses a non-mathematical approach to determine sample sizes and evaluate the selected samples.

4 0

3 years ago

On Saturday, many tickets for a hockey game were sold. Children and adult tickets were sold in the ratio of 4:7. There are 88 ti

Illusion [34]

Answer:

49 tickets

Step-by-step explanation:

THis is pretty straight forward

So we have the ratio 4:7

We know there were 88 tickets in total but we don’t know the exact amount of adult and kids

So we can Add up the ratio

4+7=11

Now we can divide 88 by 11

you’ll get 7

So by doing this we know there are 7 groups of the ratio for child to adults 4:7

So we just multiply the 7 to each

4*7

7*7

you’ll get 28:49

Now we know there are 28 kid tickets and 49 adult tickets

We know this is correct becuase if you add up the ratio, it’ll be 88

Which is the same as the amount fo people at the hockey game

6 0

3 years ago

Part I - To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nico

IRINA_888 [86]

Answer:

(I) 99% confidence interval for the mean nicotine content of this brand of cigarette is [24.169 mg , 30.431 mg].

(II) No, since the value 28.4 does not fall in the 98% confidence interval.

Step-by-step explanation:

We are given that a new cigarette has recently been marketed.

The FDA tests on this cigarette gave a mean nicotine content of 27.3 milligrams and standard deviation of 2.8 milligrams for a sample of 9 cigarettes.

Firstly, the Pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean nicotine content = 27.3 milligrams

s = sample standard deviation = 2.8 milligrams

n = sample of cigarettes = 9

$\mu$ = true mean nicotine content

Here for constructing 99% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

Part I : So, 99% confidence interval for the population mean, $\mu$ is ;

P(-3.355 < $t_8$ < 3.355) = 0.99 {As the critical value of t at 8 degree

of freedom are -3.355 & 3.355 with P = 0.5%}

P(-3.355 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 3.355) = 0.99

P( $-3.355 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $3.355 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-3.355 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+3.355 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X-3.355 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+3.355 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $27.3-3.355 \times {\frac{2.8}{\sqrt{9} } }$ , $27.3+3.355 \times {\frac{2.8}{\sqrt{9} } }$ ]

= [27.3 $\pm$ 3.131]

= [24.169 mg , 30.431 mg]

Therefore, 99% confidence interval for the mean nicotine content of this brand of cigarette is [24.169 mg , 30.431 mg].

Part II : We are given that the FDA tests on this cigarette gave a mean nicotine content of 24.9 milligrams and standard deviation of 2.6 milligrams for a sample of n = 9 cigarettes.

The FDA claims that the mean nicotine content exceeds 28.4 milligrams for this brand of cigarette, and their stated reliability is 98%.

The Pivotal quantity for 98% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean nicotine content = 24.9 milligrams

s = sample standard deviation = 2.6 milligrams

n = sample of cigarettes = 9

$\mu$ = true mean nicotine content

Here for constructing 98% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 98% confidence interval for the population mean, $\mu$ is ;

P(-2.896 < $t_8$ < 2.896) = 0.98 {As the critical value of t at 8 degree

of freedom are -2.896 & 2.896 with P = 1%}

P(-2.896 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.896) = 0.98

P( $-2.896 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.896 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.896 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.896 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.896 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.896 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $24.9-2.896 \times {\frac{2.6}{\sqrt{9} } }$ , $24.9+2.896 \times {\frac{2.6}{\sqrt{9} } }$ ]

= [22.4 mg , 27.4 mg]

Therefore, 98% confidence interval for the mean nicotine content of this brand of cigarette is [22.4 mg , 27.4 mg].

No, we don't agree on the claim of FDA that the mean nicotine content exceeds 28.4 milligrams for this brand of cigarette because as we can see in the above confidence interval that the value 28.4 does not fall in the 98% confidence interval.

5 0

3 years ago

Which situation represents a proportional relationship?​

Which situation represents a proportional relationship?