Answer:
Step-by-step explanation:
(3,1) lies below the vertex, so the parabola opens downwards.
Equation for a down-opening parabola with vertex (2,3):
y = a(x-2)² + 3, a<0
Plug in (3,1) and solve for a:
1 = a1² + 3
a = -2
y = -2(x-2)² + 3
Answer: When t = 4.25 R(t) = D(t)
This tells you that at 4.25 seconds into their flights, both the Rocket and the Drone were at a height of 20 feet.
Step-by-step explanation: The point where the two graphed lines cross is where the values are equal.
The Drone has been hovering at 20 feet between 2 and 5 seconds. The Rocket passed through that height for a brief (millisecond) time as it was falling back to the ground.
Without grid lines it is my best estimation (using a ruler to create a verticla line from the intersection of the lines to the time scale) that t = 4.25. It is between 4 and 4.5 seconds.
Answer:
They have the same rate of change.
Step-by-step explanation:
They both increase two degrees every hour.
Hi there!
Let me help you out a bit here. What we need to do is subtract the area of the smaller square from the area of the larger square. To do this, we first need to find the length of one of the larger sides. Since the outer polygon is a square, we can use the 45-45-90 relationship to determine that each side of the larger square is equal to

. Next, we can do the same thing for the smaller square, determining that one outer side of the smaller square is equal to

. To figure out the area of both squares, we need to square each of the outer lengths. This gives us 162 for the bigger square and 32 for the smaller square. Now, all we need to do is subtract 32 from 162. This gives us a value of 130cm^2 for the shaded area.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer:

Step-by-step explanation:
Let use the following trigonometric identities:

Then, the equation is simplified by substituting its components:




