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e-lub [12.9K]
3 years ago
6

Branliest to correct answer explain how to solve it please

Mathematics
1 answer:
Marysya12 [62]3 years ago
6 0

In general, nCr = n! / r! (n-r)!

Here, 7C3 = 7! / 3!(7-3)!

=7 x 6 x 5 x 4 x 3 x 2 x 1 /3 x 2 x 1 ( 4 x 3 x 2 x 1)

=7x6x5x4 / 4x3x2

=7x5x6x4 / 24

=35x24 / 24

=35

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Two right triangles are shown. First, find the missing leg of the triangle on the right. Then you have two lengths to use to fin
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Answer:

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Step-by-step explanation:

<u>GIVEN :-</u>

There are 2 right-angled triangles.

In the triangle on the right side ,

  • Hypotenuse = 26m
  • Base = 10m

In the triangle on the left side ,

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<u>TO FIND :-</u>

  • Length of the common perpendicular to both triangles.
  • Length of the hypotenuse of the triangle on the left side.

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

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<u>SOLUTION :-</u>

In the triangle on the right side ,

Perpendicular = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24m

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.

In the triangle on the left side ,

Hypotenuse = \sqrt{24^2 + 18^2} = \sqrt{576 + 324} = \sqrt{900} = 30m

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