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e-lub [12.9K]
3 years ago
6

Branliest to correct answer explain how to solve it please

Mathematics
1 answer:
Marysya12 [62]3 years ago
6 0

In general, nCr = n! / r! (n-r)!

Here, 7C3 = 7! / 3!(7-3)!

=7 x 6 x 5 x 4 x 3 x 2 x 1 /3 x 2 x 1 ( 4 x 3 x 2 x 1)

=7x6x5x4 / 4x3x2

=7x5x6x4 / 24

=35x24 / 24

=35

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gogolik [260]

Answer:

(2, 8)  and (3, 11)    --- > For example

Step-by-step explanation:

Plug in any number for x

I will use 2.

So if the equation is y = 3x + 2, then the new equation will be ...

y = 3(2) + 2

y = 6 + 2

y = 8     ----> One coordinate can be (2, 8)

Another number you could use is 3.

y = 3(3) + 2

y = 9 + 2

y = 11    ----> Another coordinate may be (3, 11)

4 0
3 years ago
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Help help help help help plss
Andreyy89

Answer:

Last one

Step-by-step explanation:

4 0
2 years ago
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A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c
olchik [2.2K]
The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in E^{c}. Find P(E^{c}).

Solution:

Part 1:

E^{c} means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

E^{c}=S-E \\  \\ 
E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\  \\ 
E^{c}=(4,5,6)

Thus the set compliment of E will contain the elements {4,5,6}.So

E^{c} = {4,5,6}

Part 2)

P(E^{c}) means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

P(E^{c}) = (Number of Elements in E^{c})/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set E^{c} = n(E^{c})=3

So, 

P(E^{c})= \frac{n(E^{c}) }{n(S)} \\  \\ 
P(E^{c})= \frac{3}{12} \\  \\ 
P(E^{c})= \frac{1}{4}
7 0
3 years ago
What is $0.8\%$ of $125\%$ of $8128$? Express your answer as a decimal.
Andre45 [30]

Answer:

<h2>81.28</h2>

Step-by-step explanation:

To solve this kind of problem, we must remember that the word "of" means multiplication in math language, and all percentages numbers can be expressed as a fraction where the denominator is 100. Applying all this, we have

0.8\%\times 125\%\times 8128\\\frac{0.8}{100}\times \frac{125}{100} \times 8128\\ 0.008(1.25)(8128)=81.28

Therefore, all those percentages of 8128 results in 81.28

5 0
3 years ago
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According to a survey , the residents of country a have approximately 179,300,000 dogs and cats as pets . The same survey report
Arte-miy333 [17]

Answer:

About 3.6 times greater.

Step-by-step explanation:

That is 1.793 * 10^8 / 5.01 * 10^7

= 1.793 / 5.01  * 10^(8-7)

= 0.36 * 10

= 3.6

5 0
3 years ago
Read 2 more answers
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