Find all the second partial derivatives. v = e5xey

1 answer:

5 0

I'm taking the liberty of editing your function v = e5xey: It should be

v = e^5x^ey, with " ^ " indicating exponentiation.

Did you mean e^(5x) or (e^5)x? I'll assume it's e^(5x).

The partial of v = e^(5x)e^y with respect to x is e^(5x)(5)*e^y, or 25x*e^y.

The partial of v = e^(5x)e^y with respect to y is e^(5x)e^y.

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Answer:

${b}^{4} + 1$

Your teacher messed up the question so just put the top right answer and ask your teacher if they did accidently miss-type.

Step-by-step explanation:

The first thing to do in this equation is look at the exponents. When multiplying a variable (or any number equal to itself with the same exponent) you only have to add the exponent. So for a, you would add the exponents to get 0, so a to the power of 0 is 1, because any number to the power of 0 is 1. For b, we would add the 3 and 1. (When no exponenet is present in a number then it is 1, so for this I added 3 and 1). So it would be 4. The correct answer is

${b}^{4} + 1$

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The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12]

Step-by-step explanation:

I beleive those options corresponds to another question, i will ignore them. We want to know an interval in which the probability that a height falls there is 0.8.

In such interval, the probability that a value is higher than the right end of the interval is (1-0.8)/2 = 0.1

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