Answer:
Step-by-step explanation:
You do not need to where the formula comes from but, just for fun, here’s a hint
To add up the numbers 1 to 10
Write out the numbers
1 2 3 4 5 6 7 8 9 10
Write them backwards
10 9 8 7 6 5 4 3 2 1
Add up both lists
11 11 11 11 11 11 11 11 11 11
This is 10 × 11 = 110
But this is twice the sum as two lots were added together
So the sum of the numbers 1 to 10 is 110 ÷ 2 = 55
ArSeqSum Notes fig4, downloadable IGCSE & GCSE Maths revision notes
The total interest earned is 40.75 and the final balance is 65.75
<u>Solution:</u>
Given, principle amount P = 25
Interest rate
Times compounded per year n = 12
Time in years t = 30

On substituting the values we get
![A = 25 [ 1+ \frac{0.0325}{12}]^{12\times30}= 25 [2.63]= 65.75](https://tex.z-dn.net/?f=A%20%3D%2025%20%5B%201%2B%20%5Cfrac%7B0.0325%7D%7B12%7D%5D%5E%7B12%5Ctimes30%7D%3D%2025%20%5B2.63%5D%3D%2065.75)
Interest I = A - P [since, A = P+I]

Answer: D is the answer
Step-by-step explanation:
D: x>2