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ivanzaharov [21]
4 years ago
8

The coordinates of the vertices of △DEF are D(2, −1) , E(7, −1) , and F(2, −3) . The coordinates of the vertices of △D′E′F′ are

D′(0, −1) , E′(−5, −1) , and F′(0, −3) . What is the sequence of transformations that maps △DEF to △D′E′F′
Mathematics
2 answers:
RUDIKE [14]4 years ago
7 0

Answer:

reflection across the y-axis and translation 2 units right. :)

Step-by-step explanation:

choli [55]4 years ago
6 0

It seems to be a reflection across line x = 1.

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I am the amount left over when a number canot be divided equally<br> answer quick
Kryger [21]

Answer:

Remainder

Step-by-step explanation:

When a number can't be divided equally, there's an amount leftover. The leftover number is called a <em><u>remainder</u></em>

I'm not really great at explaining stuff, but I hope this helps!

4 0
2 years ago
Find the two numbers whose deference is 10 and sum is 34​
mezya [45]

Answer:

the correct answer is 22 and 12

Step-by-step explanation:

5 0
3 years ago
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A farmer estimates that he has 9,000 bees producing honey on his farm. The farmer becomes concerned when he realizes the populat
grigory [225]
<span>I think the answer is The function f(x) = 9,000(0.95)x </span>
3 0
3 years ago
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7th grade math plsssssss help
Aloiza [94]

Answer:

64

Step-by-step explanation:

length(l)=8cm

breadth(b)=2cm

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5 0
3 years ago
30 POINTS! Consider the system of linear equations and the matrix equations below.
fiasKO [112]

Answer:

Option C is correct.

Step-by-step explanation:

-x+3y=2

4x-2y=22

In matrix form is represented as:

\left[\begin{array}{cc}-1&3\\4&-2\end{array}\right] \left[\begin{array}{c}x&y\end{array}\right] =\left[\begin{array}{c}2&22\end{array}\right]

AX=B

X = A^{-1}B

A^{-1} = |A|/Adj A

|A| = (-1)(-2)-(3)(4)

|A| = 2-12

|A| = -10

Adj A = \left[\begin{array}{cc}-2&-3\\-4&-1\end{array}\right]

A^-1 = -1/10\left[\begin{array}{cc}-2&-3\\-4&-1\end{array}\right]

A^-1 = 1/10\left[\begin{array}{cc}2&3\\4&1\end{array}\right]

X= A^-1 B

X = 1/10\left[\begin{array}{cc}2&3\\4&1\end{array}\right]\left[\begin{array}{c}2&22\end{array}\right]

X=1/10X=1/10\left[\begin{array}{c}2*2+3*22\\4*2+1*22\end{array}\right]\\X=1/10\left[\begin{array}{c}4+66\\8+22\end{array}\right]\\X=1/10\left[\begin{array}{c}70\\30\end{array}\right]\\X=\left[\begin{array}{c}70/10\\30/10\end{array}\right]\\X=\left[\begin{array}{c}7\\3\end{array}\right]

So, x = 7 and y =3

Hence Option C is correct.

4 0
3 years ago
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