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Andrews [41]
3 years ago
8

What is the perimeter of parallelogram WXYZ? StartRoot 5 EndRoot + StartRoot 17 EndRoot units 2 StartRoot 5 EndRoot + 2 StartRoo

t 17 EndRoot units 16 units 22 units
Mathematics
1 answer:
Marysya12 [62]3 years ago
8 0

Answer:

2 StartRoot 5 EndRoot + 2 StartRoot 17 EndRoot units

Step-by-step explanation:

The perimeter of the parallelogram is expressed as

Perimeter = WX + XY + YZ + WZ

Using the distance formula;

WX = √(0-(-1))²+(4-0)²

WX = √1²+4²

WX = √17

For XY:

XY = √(-2-(0))²+(3-4)²

XY = √(-2)²+(-1)²

XY = √4+1

XY = √5

For YZ:

YZ = √(-2+3))²+(3+1)²

YZ = √(1)²+(4)²

YZ = √1+16

YZ = √17

For WZ;

WZ = √(-3+1)²+(-1-0)²

WZ = √(-2)²+(-1)²

WZ = √4+1

WZ = √5

Perimeter = √17+√5+√17+√5

Perimeter = 2√17 + 2√5 units

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3 years ago
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<em><u>Solution:</u></em>

<em><u>Given function is:</u></em>

f(n) = 2n - 1

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f(1) = 1

There are 12 months in a year

For the second month, and third month and so on, substitute n = 2, 3 and so on

f(2) = 2(2) - 1 = 4 - 1 = 3

f(3) = 2(3) - 1 = 6 - 1 = 5

f(4) = 2(4) - 1 = 8 - 1 = 7

f(5) = 2(5) - 1 = 10 - 1 = 9

f(6) = 2(6) - 1 = 12 - 1 = 11

f(7) = 2(7) - 1 = 14 - 1 = 13

f(8) = 2(8) - 1 = 16 - 1 = 15

f(9) = 2(9) - 1 = 18 - 1 = 17

f(10) = 2(10) - 1 = 20 - 1 = 19

f(11) = 2(11) - 1 = 22 - 1 = 21

f(12) = 2(12) - 1 = 24 - 1 = 23

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Total orders = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23

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