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kipiarov [429]
2 years ago
6

Laura created a website to create T-shirts. In the first month she put up her website she had only a single T-shirt order. Each

month she got more orders. Following this function f(n)=2n-1
How many total orders did she receive over the first year?
Mathematics
1 answer:
kiruha [24]2 years ago
8 0

Laura received 144 orders over the first year

<em><u>Solution:</u></em>

<em><u>Given function is:</u></em>

f(n) = 2n - 1

Where, "n" is the month

In the first month she put up her website she had only a single T-shirt order

f(1) = 2(1) - 1 = 2 - 1

f(1) = 1

There are 12 months in a year

For the second month, and third month and so on, substitute n = 2, 3 and so on

f(2) = 2(2) - 1 = 4 - 1 = 3

f(3) = 2(3) - 1 = 6 - 1 = 5

f(4) = 2(4) - 1 = 8 - 1 = 7

f(5) = 2(5) - 1 = 10 - 1 = 9

f(6) = 2(6) - 1 = 12 - 1 = 11

f(7) = 2(7) - 1 = 14 - 1 = 13

f(8) = 2(8) - 1 = 16 - 1 = 15

f(9) = 2(9) - 1 = 18 - 1 = 17

f(10) = 2(10) - 1 = 20 - 1 = 19

f(11) = 2(11) - 1 = 22 - 1 = 21

f(12) = 2(12) - 1 = 24 - 1 = 23

<em><u>Thus total orders received over first year:</u></em>

Total orders = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23

Total orders = 144

Thus she received 144 orders over the first year

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Answer:

x = 2

Step-by-step explanation:

6x-1=11

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1: 2(y+6)=?<br> 2: 6-(-6+2)=?<br> What is the property of equation?
Citrus2011 [14]
1: 2y+12

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3 years ago
Blake said 4/5+1/3 =5/8 does his answer make sense explain. please help
Tatiana [17]
Hey there!

The answer is no because whenever you add or subtract fractions, you find the common denominator(the bottom of the fraction)

Corret way:
The common denominator is 15 (5*3)
Multiply numerator(top) and the denominator by 3 
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Multiply numerator and the denominator by 5
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7 0
3 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


5 0
3 years ago
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