Attached the solution and work.
Answer:
= 11/3
Step-by-step explanation:
1. COMBINE MULTIPLIED TERMS INTO A SINGLE FRACTION
- 7/3 (3x-2)= -21
-7 (3x-2) = -21
-----------------------
3
2. DISTRIBUTE
-7( 3x- 2) ➗ 3 =-21
3. MULTIPLY ALL TERMS BY THE SAME VALUE TO ELIMINATE FRACTION DENOMINATORS
-21x + 14 ➗ 3 = 3 (-21)
4. CANCEL MULTIPLIED TERMS THAT ARE IN THE DENOMINATOR
3 ( -21x + 14) ➗ 3 (-21)
5. MULIPLY THE NUMBERS
-21x + 14 = 3(-21)
6. SUBTRACT 14 FROM BOTH SIDES OF THE EQUATION
-21x + 14 = -63
7. SIMPLIFY
-21x = - 77
8. DIVIDE BOTH SIDES OF THE EQUATION BY THE SAME TERM
-21x/-21 = -77/-21
9. SIMPLIFY
x = 11/3
You can set up a system of equations for this problem. x= number of coach tickets and y = number of first class tickets.
$210x + $1200y = $10,230 (cost of coach ticket plus cost of first class tickets is total budget)
x + y = 11 (number of coach tickets plus number of first class tickets is total number of people)
Solve the second equation for y to get y = 11 - x, then plug that into the first equation and solve for x:
$210x + $1200(11 - x) = $10,230
$210x + $13,200 - $1200x = $10,230
-$990x + $13,200 = $10,230
-$990x = $2,970
x = 3
Sarah bought x = 3 coach tickets. Plug that into the second equation and solve for y:
3 + y = 11
y = 8
Sarah bought y = 8 first class tickets.
This is just combining like terms.....
6n2 - 5n2 + 7n2
n2 + 7n2
=8n2
