Um not really a specific enough question for a good answer, but I'll give it a go
all you have to do is use long division and divide the numerator by the denominator (top by bottom)
most often the result will not be pretty so round appropriately (i recommend tenths or hundredths)
for exampe
25/11
use some handy division skills, and you'll get about 2.27
note that improper fractions mean that the decimal form will always be greater than 1, or less than -1
30 lemon candies he give his friend.
It is given that a boy had 320 candies. There were 2 flavors. 7/16 were orange flavor and the rest were lemon. He gave his friend 30 orange candies and some lemon ones.
320 (7/16) = 140 were orange
320 - 140 = 180 were lemon
Let x be the number of lemon ones he gave away
So,
[ 140 - 30 ] / [ 180 - x ] = 11/15
110 = (11/15) ( 180 - x )
(15/11) (110) = 180 - x
150 = 180 - x
x = 180 - 150 = 30
Learn more about word problems here: brainly.com/question/20521181
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Answer:
1. Number of Hours: 0, 1, 2, 3, 4, 5
Cost In Dollars: 8, 11, 14, 17, 20, 23
2. The cost for renting a car for 10 hours is $38
3. You can rent a cart for 8 hours with $32
Answer:
a) ![[-0.134,0.034]](https://tex.z-dn.net/?f=%5B-0.134%2C0.034%5D)
b) We are uncertain
c) It will change significantly
Step-by-step explanation:
a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.
Since we assume that the variances are equal, we use the pooled variance given as
,
where
.
The mean difference
.
The confidence interval is

![= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]](https://tex.z-dn.net/?f=%3D%20-0.05%5Cpm%201.995%20%5Ctimes%200.042%20%3D%20-0.05%20%5Cpm%200.084%20%3D%20%5B-0.134%2C0.034%5D)
b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.
c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.
Answer:
r equals StartFraction C Over 2 pi EndFraction
Step-by-step explanation:
we know that
The circumference of a circle is equal to

where
r is the radius of the circle
Solve for r
That means -----> isolate the variable r
Divide by 2π both sides

Simplify right side

Rewrite

so
r equals StartFraction C Over 2 pi EndFraction