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Tomtit [17]
4 years ago
15

Improper fraction as decimal

Mathematics
1 answer:
Andru [333]4 years ago
4 0
Um not really a specific enough question for a good answer, but I'll give it a go
all you have to do is use long division and divide the numerator by the denominator (top by bottom)
most often the result will not be pretty so round appropriately (i recommend tenths or hundredths)
for exampe
25/11
use some handy division skills, and you'll get about 2.27
note that improper fractions mean that the decimal form will always be greater than 1, or less than -1
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ira [324]

In order to be continuous everywhere, we only need to satisfy continuity at x=10. For that to happen, we need to have

\displaystyle\lim_{x\to10^-}f(x)=\lim_{x\to10^+}f(x)=f(10)

By the function's definition, f(10)=2(10)-2=18. Compute the limits:

\displaystyle\lim_{x\to10^-}f(x)=\lim_{x\to10}2x-2=18

\displaystyle\lim_{x\to10^+}f(x)=\lim_{x\to10}-8x+b=-80+b

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18=b-80\implies b=98

3 0
3 years ago
I will give you a good amount of points if you answer this correct​
Colt1911 [192]

Answer:

I think the answer is B. The equation has infinitely many solutions.

Step-by-step explanation:

4(3x + 4) = 15x + 12 - 3x + 4

*group like terms so 4(3x+4) = 15x - 3x + 12 + 4

*add similar elements 15x - 3x = 12x

*add the numbers 12 + 4 = 16

*Expand to 12x + 16 - 16 = 12x + 16 - 16

*You simplify 12x = 12x

*Subtract 12x from both sides

*Then Simplify which is 0

Which means Both sides are equal to 0

True for all X

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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