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Ivanshal [37]
2 years ago
8

Solve 5kx + 6 = 7kx for x.

Mathematics
1 answer:
Slav-nsk [51]2 years ago
4 0

Answer:

5kx + 6 = 7kx  

 

Subtract 6 on both sides  

 

5kx + 6 - 6 = 7kx - 6

5kx = 7kx - 6

 

Then subtract 7kx on both sides

5kx - 7kx = 7kx - 6 - 7kx  

-2kx = -6  

 

Now divide by -2k on both sides

-2kx/-2k = -6/-2k

x = -6/-2k

Simplify

x = 3/k  

These are algebriac equations that you keep doing. Maybe try practicing the simpiler algebriac equations then slowely do more complicated ones. Just letting you know.

Step-by-step explanation:

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If a cookie recipe that makes 2 dozen cookies calls for 2 1/4 cups of flour, how cups of flour do you need to make 5 dozen cooki
Schach [20]

Answer:

5. 5/8 flour needed to make 5 dozen cookies

Step-by-step explanation:

2 dozen= 24

5 dozen=60

It takes 1 1/8 flour for 1 dozen cookies so 1 1/8 x 5= 5.625 in fraction form that= 5 5/8

5 0
2 years ago
The produce market is having a sale on grapes and oranges. A customer found the following two receipts in her cart as she was wa
AleksandrR [38]

Answer:

Step-by-step explanation:

From the first receipt:

2 pounds of grapes + 4 pounds of oranges = 10.70 which, in an algebraic equation, looks like this:

2g + 4o = 10.70

From the second receipt:

3 pounds of grapes + 2 pounds of oranges = 9.65 which, in an algebraic equation, looks like this:

3g + 2o = 9.65

Putting those together into a system and solving using the elimination method:

2g + 4o = 10.7

3g + 2o = 9.65

I am going to eliminate the oranges first since it's easier to do that. I will multiply the second equation by -2 to get a new system:

2g + 4o = 10.7

-6g - 4o = -19.3

As you can see, the oranges are eliminated because 4o - 4o = 0o. That leaves us with only the grapes:

-4g = -8.6 so

g = 2.15

Grapes cost $2.15 per pound. Now sub that into either one of the original equations to solve for the cost per pound of oranges:

2(2.15) + 4o = 10.7 and

4.3 + 4o = 10.7 and

4o = 6.4 so

o = 1.60

Oranges cost $1.60 per pound. That is choice D from your list.

5 0
3 years ago
Francesca leaves her home and Drive South 150 km. Then she drives West 70 km. At this point, she drives North 30 km. Finally, sh
Sveta_85 [38]

To find the distance between her home and her latest position:

According to the question, the diagram is,

Consider the right triangle,

AB=120 km

BC=50 km

To find AC:

Using Pythagoras theorem,

\begin{gathered} AC^2=AB^2+BC^2_{} \\ =120^2+50^2 \\ =14400+2500 \\ =16900 \\ =130\text{ km} \end{gathered}

Hence, the distance between the new position and her home is 130 km.

8 0
1 year ago
Can anyone help me on this problem? Please it doesn’t make sense to me...
Sav [38]

Answer:

6

Step-by-step explanation:

Cost per item is found by dividing the cost by the number of items. If the woman bought n items for $120, the cost of each item is $120/n. If the woman bought 24 more items, n+24, at the same price, then the cost per item is $120/(n+24). The problem statement tells us this last cost is $16 less than the first cost:

120/(n+24) = (120/n) -16

Multiplying by n(n+24) gives ...

120n = 120(n+24) -16(n)(n+24)

0 = 120·24 -16n^2 -16·24n . . . . . . subtract 120n and collect terms

n^2 +24n -180 = 0 . . . . . . . . . . . . . divide by -16 to make the numbers smaller

(n +30)(n -6) = 0 . . . . . . . . . . . . . . factor the quadratic

The solutions to this are the values of n that make the factors zero: n = -30, n = 6. The negative value of n has no meaning in this context, so n=6 is the solution to the equation.

The woman bought 6 items.

_____

Check

When the woman bought 6 items for $120, she paid $120/6 = $20 for each of them. If she bought 6+24 = 30 items for the same money, she would pay $120/30 = $4 for each item. That amount, $4, is $16 less than the $20 she paid for each item.

3 0
3 years ago
Any help would be greatly appreciated
aleksandr82 [10.1K]

Answer:

\boxed{\sf \ \ \ 49a^8b^6c^2 \ \ \ }

Step-by-step explanation:

Hello,

(-7a^4b^3c)^2=(-1)^27^2a^{4*2}b^{3*2}c^2=49a^8b^6c^2

as

(-1)^2=1

8 0
3 years ago
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