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slavikrds [6]
3 years ago
11

Which number would make this number sentence true?

Mathematics
1 answer:
sveticcg [70]3 years ago
7 0

Answer:

D. 8

Step-by-step explanation:

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A school team won 80% of its matches. Out of all the matches played, the team won 40 matches. How many matches did the soccer te
sergij07 [2.7K]

Answer:

50 games

Step-by-step explanation:

(sorry if it makes so sense) The reason of this is because you know that 80%=40 matches so you need to find what the other 20% was... What I did was multiply 50 x .80 to see if it wave me 40 and it did.

3 0
4 years ago
(04.01)The Baldwin family walked of a mile in of an hour. What is their unit rate in miles per hour?
laiz [17]
So walked 4/5 mile in a 4/9 h  so just use the rule of 3 simple 

60 minutes ------ 1 hour
x min. ----------- 4/9 h
--------------------------------
x = 4/9 *60/1 = 240/9 =  26,6 min. 

4/5 mile -------in 26,6 min.
1 mile --------   x min.
-----------------------------
x = 1*26,6/(4/5) = 26,6 /(0,8) = 33,25 min. 

1 mile ..... 33,25 min.
x miles ----- 60 min.
---------------------------
 x = 60/33,25 = 1,8 miles 

so their unit rate in miles per hour will be 1,8 miles / hour 

hope this will help you 
3 0
3 years ago
Read 2 more answers
Simplify by rationalizing the denominator.<br> 15√2 / √270
ladessa [460]

\frac{ \sqrt{15} }{3} ✅

Step-by-step explanation:

\frac{15 \sqrt{2} }{ \sqrt{270} }  \\ \\ =  \frac{15 \sqrt{2} }{ \sqrt{270} }   \times  \frac{ \sqrt{270} }{ \sqrt{270} }  \\  \\=  \frac{15 \sqrt{2}  \times  \sqrt{270} }{270}  \\\\ (∵ \sqrt{a}  \times  \sqrt{a}  = a) \\\\  =  \frac{15 \sqrt{540} }{270}  \\  \\=  \frac{ \sqrt{2 \times 2 \times 3 \times 3 \times 3 \times 5} }{18}  \\ \\ =  \frac{ \sqrt{ {2}^{2} \times  {3}^{2}  \times 15 } }{18}  \\  =  \frac{2 \times 3 \sqrt{15} }{18}  \\ \\ =  \frac{6 \sqrt{15} }{18}  \\ \\ =  \frac{ \sqrt{15} }{3}

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}

7 0
3 years ago
Read 2 more answers
Find the average value of the function f(t)=cos13(5t)sin(5t) f(t)=cos13⁡(5t)sin⁡(5t) on the interval [4,10].
Vilka [71]
The average value is given by

\displaystyle\frac1{10-4}\int_4^{10}\cos^{13}5t\sin5t\,\mathrm dt

Setting y=\cos5t, you get \mathrm dy=-5\sin5t\,\mathrm dt, and the integral becomes

\displaystyle-\frac1{30}\int_{\cos20}^{\cos50}y^{13}\,\mathrm dy
=-\dfrac1{30}\dfrac{y^{14}}{14}\bigg|_{y=\cos20}^{y=\cos50}
=-\dfrac{\cos^{14}50-\cos^{14}20}{420}\approx-0.00145
6 0
4 years ago
I
DiKsa [7]

Answer:

no clue....

Step-by-step explanation:

4 0
3 years ago
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