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maks197457 [2]
3 years ago
13

Solve for x if both sides are similar

Mathematics
2 answers:
Alex777 [14]3 years ago
7 0
The answer is x=12 ! Hope this helped
kodGreya [7K]3 years ago
4 0

Answer:

x = 12

Step-by-step explanation:

we can put this is a proportion: (new side 1) / (old side 1) = (new side 2) / (old side 2)

so in this case, 18 would be old side 1, x would be new side 1

12 would be old side 2, and 8 would be new side 2

plug these in: x/18 = 8/12

cross multiply 18 and 8: x = 144/12

now simplify: x = 12

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Write the algebraic expression. twice the sum of x and 4
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Answer: Y= X+4•2

Word form: Y equals X plus 4 times 2
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Find the value of r so the line that passes through each pair of points has the given slope.
padilas [110]

Answer:

<em>- 4</em>

Step-by-step explanation:

( 3 - r ) / ( 1 + 5) = 7/6

\frac{3-r}{1+5} = \frac{7}{6} ⇒ 3 - r = 7 ⇒ r = <em>- 4</em>

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Jaclyn used the slope formula to find the slope of the line through the points given in the table. In which step did Jaclyn make
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Read 2 more answers
A robot has a straight arm 20 inches long that can rotate about the origin of a coordinate system. If the robot’s hand is locate
scoundrel [369]

Answer:

The location of the robots hand after rotating 45° counterclockwise from (-20, 0) in inches is (-14.14, 14.14)

The location of the robots hand after rotating 45° clockwise from (-20, 0)) in inches is (-14.14, -14.14)

Step-by-step explanation:

The initial location of the robots hand = (-20, 0)

The angle through which the robot rotates his hand = 45°

∴ We have the length of the robots hand = 20 inches

We note that (-20, 0) is in the 2nd Quadrant

The location of the robots hand after rotating 45° counterclockwise = 135°

Therefore, the location of the robots hand after the rotation = (20×cos(135°), 20×sin(135°)) = (-10·√2, 10·√2) = (-14.14, 14.14)

The location of the robots hand after rotating 45° clockwise from (-20, 0) = 225°

Therefore, the location of the robots hand after the rotation = (20×cos(225°), 20×sin(225°)) = (-10·√2, -10·√2) = (-14.14, -14.14)

8 0
3 years ago
What is the equation of the following graph?
boyakko [2]

Answer:

\frac{(x-1)^2}{5^2} -\frac{(y-2)^2}{2^2} =1

Step-by-step explanation:

Here you are require to find the equation of the hyperbola given that the center (h,k), the coordinates of the vertices and those of the co-vertices can be determined from the diagram given

The sharp turning points of the curves give the vertices at (-4,2) and (6,2)

Joining the vertices with a straight line will form the transverse axis with length 2a .

To find the length of the transverse axis 2a will be ; 6--4=10. 2a=10 hence a=10/2 =5

a=5

Find the center of the hyperbola at (h,k) by  finding the intersecting point of the diagonals of the rectangle in the diagram

The center identified will be (h,k) = (1,2)

To find the length of the conjugate axis 2b will be ; the length between points (1,4) and (1,0) which are the coordinates of the co-vertices in the hyperbola. 2b= 4-0=4 , b=4/2 = 2

b=2

The standard equation of the hyperbola with center (h,k) is written as ;

\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1

where  (h,k) is center of hyperbola, (h±a,k) is coordinate of the vertices and (h,k±b) are coordinates of co-vertices.

Substitute values of a, b, h, and k in equation as

\frac{(x-1)^2}{5^2} -\frac{(y-2)^2}{2^2} =1

7 0
3 years ago
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