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Alex17521 [72]
3 years ago
9

Help me I'm bout to breakdown on this and cry help I'm rlly not ok​

Mathematics
2 answers:
matrenka [14]3 years ago
7 0

Answer: 3/5 is the correct answer

MrRissso [65]3 years ago
3 0

Answer:

বাংলা ৬ নাম্বার প্রশ্নের উওর টা কি

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3 years ago
1. A weight of 18,000 lb is supported on a rectangular base plate that is 9 in. wide and 2 ft long. The base plate rests on a co
slega [8]

Answer:

a) 83.3\ lb/in^2

b) 12000\ lb/ft^2

Step-by-step explanation:

Given : A weight of 18,000 lb is supported on a rectangular base plate that is 9 in. wide and 2 ft long. The base plate rests on a concrete slab.

To find : Determine the stress that the base plate exerts on the concrete slab. Express your answer in units of (a) lb/in². and (b) lb/ft².

Solution :

a) A rectangular base plate that is 9 in. wide and 2 ft long.

Converting ft into inches,

1 feet = 12 inch

2 feet = 2×12= 24 inch

The area of the rectangular base is A=l\times b

A_1=24\times 9

A_1=216\ in^2

The weight is W=18,000 lb.

The stress that the base plate exerts on the concrete slab is given by,

S=\frac{W}{A_1}

S=\frac{18000\ lb}{216\ in^2}

S=83.3\ lb/in^2

b) A rectangular base plate that is 9 in. wide and 2 ft long.

Converting inches into ft,

1 inch = \frac{1}{12}\ ft

9 feet = \frac{9}{12}=0.75\ ft

The area of the rectangular base is A=l\times b

A_2=2\times 0.75

A_2=1.5\ ft^2

The weight is W=18,000 lb.

The stress that the base plate exerts on the concrete slab is given by,

S=\frac{W}{A_2}

S=\frac{18000\ lb}{1.5\ ft^2}

S=12000\ lb/ft^2

5 0
3 years ago
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