All categories

3 years ago

Find the values of m and n that make equation true. 8+15i=2m+3ni

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

8 0

gthy67jntgrt67u89i7yu holfcedikjnhfnhtfrolwsfr n/lkjhfwr3n oljfu vikr8hneikoeOPDTE85417

+TE4TE

You might be interested in

Find the probability of 5 successes in 9 trials of a

erik [133]

Answer:

13.8%

Step-by-step explanation:

P = nCr pʳ qⁿ⁻ʳ

P = ₉C₅ (0.37)⁵ (1−0.37)⁹⁻⁵

P ≈ 0.138

3 0

2 years ago

How would I find the value of X in this equation

slava [35]

Sum of angles In all triangles are 180....line DAC is horizontal and therefore is 180 degrees ....so minus 180 degrees from 105 and you get 75 degrees....and since the sum of all angles in a triangle is 180...add 75 and 67 which would be 142 degrees ...then minus 142 from 180 degrees to get 38 degrees for x

4 0

2 years ago

Help !!!!!! Need to know ASAP

madreJ [45]

Answer:

Multiply by 5

5*2f-5*6g=10f-30g

5 0

2 years ago

The measure of angle 1 is 39 degrees. What is the measure of the angle adjacent to angle<br> 1?

Bogdan [553]

Answer:

Step-by-step explanation:

90-39 = 51

6 0

2 years ago

Jake has a rectangular garden that measures 12 feet by 14 feet. He wants to increase the area by 50% and plans to increase each

emmasim [6.3K]

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

$x\approx 2.9ft$

<h2>Explanation:</h2><h2 />

First of all, let's calculate the area of the original rectangular garden:

$A=b\times h \\ \\ b:base \\ \\ h:height \\ \\ \\ b=12ft \\ \\ h=14ft \\ \\ \\ A=12(14) \\ \\ A=168ft^2$

Jake wants to increase the area by 50%, so the new area would be:

$A'=168(1.5) \\ \\ A'=252ft^2$

He wants to increase the area by 50% and plans to increase each dimension by equal lengths, x, so this is represented by the figure below, therefore:

$(12+x)(14+x)=252 \\ \\ 168+12x+14x+x^2-252=0 \\ \\ x^2+26x-84=0 \\ \\ \\ Using \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ \\ b=26 \\ \\ c=-84 \\ \\ \\ x=\frac{-26 \pm \sqrt{26^2-4(1)(-84)}}{2(1)} \\ \\ x=\frac{-26 \pm \sqrt{1012}}{2} \\ \\ \\ Two \ solutions: \\ \\ x_{1}=-13+\sqrt{253} \approx 2.9\\ \\ x_{2}=-13-\sqrt{253} \approx -28.9 \\ \\ x_{2} \ is \ discarded \ because \ it \ can't \ be \ negatives$

Finally:

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

$x\approx 2.9ft$

<h2>Learn more:</h2>

Dilation: brainly.com/question/10945890

#LearnWithBrainly

6 0

2 years ago