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2 years ago

Graph the line that passes through the points (-5,1) and (5,-5) 1

Mathematics

1 answer:

11Alexandr11 [23.1K]2 years ago

6 0

Answer:

It would be a diagnol line.

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Ludmilka [50]

Can't really see it, can you show it to me more?

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3 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

shusha [124]

Answer:convergent

Step-by-step explanation:

Given

Improper Integral I is given as

$I=\int_{-\infty}^{0}1000e^xdx$

$I=1000=\int_{-\infty}^{0}e^xdx$

integration of $e^x$ is $e^x$

$I=1000\times \left [ e^x\right ]^{0}_{-\infty}$

$I=1000\times I=\left [ e^0-e^{-\infty}\right ]$

$I=1000\times \left [ e^0-\frac{1}{e^{\infty}}\right ]$

$I=1000\times 1=1000$

so the integration converges to 1000 units

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3 years ago

What is the solution to this expression<img src="https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7Bx%5E%7B2%7D%20%5Ccdot%20t%7D%20%20%5Cf

ankoles [38]

Answer:

4/xt 3 sqaured

Step-by-step explanation:

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3 years ago

Find the area to this problem

Westkost [7]

Answer:

120

Step-by-step explanation:

area = 15 x 8

8 0

3 years ago

Read 2 more answers

What is the quadratic in vertex form that has a vertex of (-1, 5)<br><br> Options in image

dimaraw [331]

Answer:

Third option

$y = (x+1) ^ 2 + 5$

Step-by-step explanation:

In this case we must write a quadratic equation in the vertex form.

We have the vertice. (-1, 5)

We know that the vertex form for a quadratic equation is:

$y = (x-h) ^ 2 + k$ .

Where (h, k) is the vertex.

So if the vertex is (-1, 5), the equation sought is:

$y = (x-(-1)) ^ 2 + 5$

$y = (x+1)) ^ 2 + 5$

Therefore the answer is the Third option.

5 0

3 years ago

Read 2 more answers