68% fall within +/- 1 SD, so men above that 1 SD (165) are: (100-68)/2
32/2 = 16% above 165 and also 16% below 135
Answer:
The player with the most runs had a rush of 1,240 yards
Step-by-step explanation:
In this question, we are asked to calculate the number of yards that was rushed by one of two person given their combined run and an extra information.
Firstly, let the person that had the smaller number of rush have a rush of x rushes. The second person has a rush of 4 times the other. This makes a number of 4x rushes
By adding both together, we have a total of 1550 yards
Mathematically, this means that x + 4x = 1550
5x = 1550
x = 1550/5 = 310 rushes
The second player had a rush of 4x and that is 4 * 310 = 1,240 rushes
C ≈ 307.88
Hope that helps.
Answer:Find the distance between the parallel lines m and n whose equations are y = x + 4 and y = x - 6, respectively.
There are several ways to do this...here's one
Let (0, 4) be a point on the first line
Then.......a line with a negative reciprocal slope going through this point will have the equation :
y = -x + 4........so......we can find the intersection of this line with y = x - 6....set both equations equal
-x + 4 = x - 6 add x, 6 to both sides
10 = 2x divide both sides by 2
5 = x
So...using -x + 4, the y value at intersection = -1.......
So...we just need to find the distance from (0,4) to ( 5, -1) =
√[ (5)^2 + (4 + 1)^2 ] = 5√2 ≈ 7.07 units
Here's a pic....AB is the distance with A = (0,4) and B = (5, -1)
Step-by-step explanation:
