Answer: Aggressive
Explanation:
Aggressive separation strategies are the technique that involves confrontation and intense feeling for separating something from others.
- This technique includes action like attacking, assaultive, confronting etc.for segregation.
- Co-culture segregation is separation of a subset of culture from large and major culture.In this culture, there can be more than two types of culture that are split forcefully through barrier.
- Thus, co-culture segregation uses the methodology of aggressive separation.
The total number of chars in each string is basically the size of each string.
Using JAVA:
String[] arr = {"hello", "my", "name", "is", "Felicia"}; int count = 0; for(int i = 0; i < arr.length; i++) { count = count + arr[i].length(); System.out.println("Characters in " + arr[i] + ": " + count); }
Output:
<span>Characters in hello: 5
Characters in my: 7
Characters in name: 11
Characters in is: 13
Characters in Felicia: 20</span>
Answer:
a) D = 4.88 * 10^(-14) m^2 / s
b) <em>t </em>= 1.1 hr
Solution:
a) Magnesium in Aluminum diffusion:
D = Do * exp(-Qd / RT)
= (1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15)
= 4.88 * 10^(-14) m^2 / s
D = 4.88 * 10^(-14) m^2 / s
b) The composition remains same at say the distance Xo:
(Cx - Co) / (Cs - Co) = Constant
Xo^2 / D_{550} * <em>t </em>= Xo^2 / D_{450} * 15
D_{550} * <em>t </em>= D_{450} * 15
(1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15) * <em>t</em>
(4.88 * 10^(-14) m^2 / s) * 15
by, solving for <em>t </em>we get:
<em>t </em>= 1.1 hr
So, the time required is 1.1 hr.
Answers- My computer, My Documents and Recyle bin.
2,3,4 option
