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Oduvanchick [21]

4 years ago

5

If X=5 and 5=y, then x=y Ar algebraic equality property justifies the above statement?

1 answer:

RUDIKE [14]4 years ago

3 0

Answer:

Yes.

Step-by-step explanation:

According to the Transitive property of the Algebraic properties of equality, two values are said to be equal is they are differently equal to a corresponding third party. This is, If a=b and b=c then a=c.

Hence, if x=5 and 5=y, then following the transitive property of Algebraic properties of equality, x=y, hence the Algebraic property of equality Justifies the statement.

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Evaluate -(7-3)(75).

SIZIF [17.4K]

Answer:

-300

Step-by-step explanation:

<em><u>The first step is to distribute the -1 to (7 - 3), like so:</u></em>

-(7 - 3) (75)

-7 + 3(75)

<em><u>Add like terms (-7 and 3):</u></em>

-4(75)

-300

8 0

3 years ago

Read 2 more answers

Find an equation of the tangent to the curve at the given point by both eliminating the parameter and without eliminating the pa

jek_recluse [69]

Answer:2x-y=5

Step-by-step explanation:

Given

$x=6+\ln t$

$y=t^{2}+6$

$\left ( a\right )$ without eliminating parameter

$\frac{\mathrm{d} x}{\mathrm{d} t}$ = $\frac{1}{t}$

$\frac{\mathrm{d} y}{\mathrm{d} t}$ =2t

$\frac{\mathrm{d} y}{\mathrm{d} x}=2t^2$

at $\left ( 6,7\right )$

6=6+ $\ln\left ( t\right )$

t=1

Equation of line is given by

2= $\frac{y-7}{x-6}$

2x-12=y-7

2x-y=5

$\left ( b\right )$ by eliminating parameter

$x-6=\ln \left ( t\right )$

$t=e^{x-6}$

$y=t^2 +6$

$y=e^{\left ( 2x-12\right )}+6$

differentiating we get

$\frac{\mathrm{d}y}{\mathrm{d} x}=2e^\left ( 2x-12\right )$

$at \left ( 6,7\right )$

$\frac{\mathrm{d}y}{\mathrm{d} x}=2$

$2\left ( x-6\right )=\left ( y-7\right )$

2x-y=5

4 0

3 years ago

30 mi / h = ____ ft / min. Please help.

Setler [38]

30 mi/h= 180 mi/min= 950400 ft/min

3 0

4 years ago

The body of a 154-pound person contains approximately milligrams of gold and milligrams of aluminum. based on this information,

Lady_Fox [76]

This question is incomplete

Complete Question

The body of 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum.

Based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?

Answer:

300 times

Step-by-step explanation:

From the above question, we are told:

The body of 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum.

We create a proportion

2 × 10^-1 mg of gold : 6 × 10^1 mg of aluminum

= 0.2 mg of gold : 60 mg of aluminum

Therefore, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body is calculated as:

60mg ÷ 0.2 mg

= 300

Therefore, the number of milligrams of aluminum in the body is 300 times the number of milligrams of gold in the body

8 0

4 years ago

What is a square plus b square equal c square

evablogger [386]

That is the Pythagorean’s theorem, used to find the largest side on a right (90 degree) triangle.

4 0

3 years ago