Answer:
a) P=0.019
b) P=0.263
c) P=0.794
Step-by-step explanation:
We assume that the poll gives the population's proportion of respondents said that their jobs were sometimes or always stressful (p=0.8).
Then, a sample of size n=190 is taken.
The sample mean is:
The sample standard deviation is:
The probability that 140 or fewer workers find their jobs stressful is:
Note: a correction for continuity is applied.
The probability that more than 155 workers find their jobs stressful is
The probability that the number of workers who find their jobs stressful is between 145 and 158 inclusive is:
Answer:
-50/7
Step-by-step explanation:
I dont know what u want me to do but this is what happens when u evaluate it
19. C. 10,12 (D is eliminated because 15 is greater than 12, greatest common factor of the others was not 2)
20. C. 42 (The largest integer that can divide into both)
Answer:
x is less than or equal to -23
Step-by-step explanation:
-x is greater than or equal fo 23 divide negative on both sides
x is less than or equal to -23
(srry i don't have the inequality signs)
Answer:
The value of the snack bar is $ 2 and that of the magazine subscription is 25 $
Step-by-step explanation:
We have a system of two equations and two unknowns, which would be the following:
let "x" be the cost of the snack bar
Let "y" be the cost of the magazine subscription
16 * x + 4 * y = 132
20 * x + 6 * y = 190 => y = (190 - 20 * x) / 6
replacing:
16 * x + 4 * (190 - 20 * x) / 6 = 132
16 * x + 126.66 - 13.33 * x = 132
2.66 * x = 132 - 126.66
x = 5.34 / 2.66
x = 2
for "y":
y = (190 - 20 * 2) / 6
y = 25
Which means that the value of the snack bar is $ 2 and that of the magazine subscription is 25 $
