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nirvana33 [79]
3 years ago
12

Select the correct answer. The number of oranges purchased varies directly as the price of the oranges. If 11 oranges cost $2.35

, what is the cost of 18 oranges? A. $3.85 B. $85.71 C. $84.24 D. $2.35
Mathematics
2 answers:
Vlad1618 [11]3 years ago
7 0

Answer:

A. 3.85

Step-by-step explanation:

  • If 11 oranges cost $2.35, we could calculate the cost of each of these oranges, simply dividing the total cost ($2.35) between the amount of oranges bougth (11). This will give us the cost of a single orange, that is, the  unitary cost= \frac{2.35}{11}= 0.21.
  • Then, if we want to know the cost of 18 oranges, we just have to multiply the cost of a single orange (0.21) by 18: 0.21x18 = 2.85
Fudgin [204]3 years ago
6 0

Answer:

Step-by-step explanation:

3.85

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<h3>Answer:  42</h3>

Explanation:

We have y = -0.9x^2 + 76x - 250 which is in the form y = ax^2+bx+c

where,

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The vertex (h,k) is when the profit is maxed out.

h = -b/(2a)

h = -76/(2(-0.9))

h = 42.222 approximately

Let's plug in x values around x = 42

Try x = 41

y = -0.9x^2 + 76x - 250

y = -0.9(41)^2 + 76(41) - 250

y = 1353.10

Now try x = 42

y = -0.9x^2 + 76x - 250

y = -0.9(42)^2 + 76(42) - 250

y = 1354.4

Now try x = 43

y = -0.9x^2 + 76x - 250

y = -0.9(43)^2 + 76(43) - 250

y = 1353.9

We see that the largest profit happens when x = 42.

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