9x²-0x-4
=9x²-4
=(3x-2)(3x+2) is the factor form of 9x²-0x-4
Solve for x:
3x-2=0
Add 2 to each side
3x-2+2=0+2
3x=2
Divided 3 to each side
3x/3=2/3
x=2/3
Or
3x+2=0
Subtract 2 to each side
3x+2-2=0-2
3x=-2
Divided 3 to each side
3x/3=-2/3
x=-2/3. Hope it help!
Duh -37 Because 37-9 is 37 and so the answer is -37
Answer:
If you were solving the right triangle, it would be:
m∠A = 46°
m∠B = 44°
m∠C = 90°
AB = 32
BC ≈ 23
AC ≈ 24
Step-by-step explanation:
To solve this right triangle, you can use trigonometric ratios to solve for the sides. To find the angle measures:
m∠A = 46° (given)
m∠B = x
m∠C = 90° (given)
180 - (46 + 90) = x
180 - 136 = x
44 = x
m∠B = 44°
To find the side measures, you can use tangent, sine, cosine, and the Pythagorean Theorem.
Recall that:
tangent = opposite side/adjacent side
sine = opposite side/hypotenuse
cosine = adjacent side/hypotenuse
So:
sin46 = BC/32
BC = 32 (sin46)
BC ≈ 23
tan46 = BC/AC
AC = BC/tan46
AC = (23.01887361...) (tan46)
AC ≈ 24
Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
You only need two numbers to do that.
The numbers are 16 and -3 .
16 - 3 = 13
(16) x (-3) = -48
