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Romashka-Z-Leto [24]

2 years ago

15

A recipe for sparkling grape juice calls for 1 1\2 quarts of water and 3\4 quarts of grape juice. How much sparkling water would

you need to mix with 9 quarts of grape juice?

1 answer:

WITCHER [35]2 years ago

4 0

Answer:

You will need 18

Step-by-step explanation:

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Find the slope of the line that passes through (14, -26) and (15, 14).

tatuchka [14]

Answer:

Slope is 40

Full equation: y=40x-586

Step-by-step explanation:

Slope is y2-y1/x2-x1

14 is x1

-26 is y1

15 is x2

14 is y2

14-(-26)/15-14

40

So the slope is 40

To find the equation

y=40x+b

14=15(40)+b

14=600+b

b=-586

Equation:

y=40x-586

5 0

3 years ago

What is 34 & 3/4 inches divided by 2 equal

Sever21 [200]

Answer:

17 and 3/8 inches

Step-by-step explanation:

..............................

(34+3/8)/2=17+3/16

plz....

mark it as a brilliant answer

7 0

2 years ago

How to substitute x=-2 and x=5 into 2x^2+6-20=0 to check my work

Komok [63]

First answer (x=-2)
...
(2)[(-2)^2]+6-20
2(4)+6-20
8+6-20
14-20
<em>-6 (answer)
</em><em>
</em><em />Second answer (x=5)
...
(2)[(-5)^2]+6-20
2(25)+6-20
50+6-20
56-20
<em>36 (answer)
</em>Hope this helps!

4 0

3 years ago

Michael wants to rent a boat and spend less than $53 the boat cost six dollars per Michael wants to rent a boat and spend less t

ASHA 777 [7]

Hi hope I helped, ok so first 6×7=42 and its less than 53 so ur answer is 42

5 0

3 years ago

Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx

ikadub [295]

Answer:

<em>Explicación más abajo</em>

Step-by-step explanation:

Integración Indefinida

La integral

$I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}$

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

$I=sen(t)-t.cos(t)+C$

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

$cos(t)=\sqrt{1-sen^2(t)}$

Entonces:

$cos(t)=\sqrt{1-x^2}$

Devolviendo los cambios:

$I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C$

Es la respuesta correcta

7 0

2 years ago