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My name is Ann [436]
3 years ago
14

If ƒ(x ) = x^2 + 1 and g(x ) = 3x + 1, find [ƒ(2) - g(1)]^2. 1 2 9

Mathematics
2 answers:
stepladder [879]3 years ago
5 0
I think that the answer would be 2 if I am right 
Daniel [21]3 years ago
5 0

Does this help?

If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find [ƒ(2)-g(1)] 2

Anwser: 1

((2)2 + 1) - (3(1) + 1) = 1

/ / | | \ \ | |

2*2=4+1 - 3*1=3+1 =1

\ / \ /

5 - 4 =1

5-4=1

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I really don't understand this I need help
Salsk061 [2.6K]
In looking at it I would guess it is asking which of the points is on the line? To answer that you would have to take each point an plug it into the equation and see if it is true.

3x - 7 = y

A(9,20)  
3(9) - 7 = 20
27 - 7 = 20
20 = 20 True - this point is on the line

B(5,0)
3(5) - 7 = 0
15 - 7 = 0
8 = 0 False - this point is not on the line

C(3,2)
3(3) - 7 = 2
9 - 7 = 2
2 = 2  True - this point is on the line

I hope this helps
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4vir4ik [10]
Its 15 boats bcuz...252+288=540 and 540/36= 15 boats :D
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3 years ago
1<br> a) 7 x 5/6 work out and simplify
hjlf

7 5 35

-- X -- = -----

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hope it helps

7 =7/1

Multiplying Fractions is easy . numerator times numerator and denominator times denominator. then simplify if possible

8 0
3 years ago
Read 2 more answers
Let y be a random variable with p(y) given in the accompanying table. find e(y ), e(1/y ), e(y 2 − 1), and v(y ). y 1 2 3 4 p(y)
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<span>E[Y] = 0.4·1 + 0.3·2 + 0.2·3 + 0.1·4 = 2 E[1/Y] =0.4·1/1 + 0.3·1/2 + 0.2·1/3 + 0.1·1/4 = 0.4 + 0.15 + 0.0666 + 0.025?0.64 V[Y] =E[Y2]-E[Y]2= (0.4)·12+(0.3)·22+(0.2)·32+(0.1)·42-22= 0.4+1.2+1.8+1.6-4= 5-4 = 1</span>
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