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My name is Ann [436]
3 years ago
14

If ƒ(x ) = x^2 + 1 and g(x ) = 3x + 1, find [ƒ(2) - g(1)]^2. 1 2 9

Mathematics
2 answers:
stepladder [879]3 years ago
5 0
I think that the answer would be 2 if I am right 
Daniel [21]3 years ago
5 0

Does this help?

If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find [ƒ(2)-g(1)] 2

Anwser: 1

((2)2 + 1) - (3(1) + 1) = 1

/ / | | \ \ | |

2*2=4+1 - 3*1=3+1 =1

\ / \ /

5 - 4 =1

5-4=1

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Someone pls help:>>
Charra [1.4K]
<h3>Answer:  n^2 + 1</h3>

Explanation:

Imagine that you cross out the top-most square for each step of each diagram. The squares not crossed out have the following counts: 1, 4, 9

This is the sequence of perfect squares. So the rule will have us take the number n, and square it to get n^2. Then we add on the squares we crossed out earlier. This explains the "plus 1" at the end to get the answer of n^2+1

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6 0
3 years ago
Which is 625 written as a power of 5 (exponets) A. 4*5 B.3*5 C.5*3 D.5*4
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<span>625 written as a power of 5 = 5^4
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