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mars1129 [50]
2 years ago
5

In this triangle, the product of sin B and tan C is and the product of sin Cand tan B is

Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
7 0

Answer:

\frac{c}{a} and \frac{b}{a}

Step-by-step explanation:

sinB = \frac{opposite}{hypotenuse} = \frac{AC}{BC} = \frac{b}{a}

tanC = \frac{opposite}{adjacent} = \frac{AB}{AC} = \frac{c}{b}

Thus

sinB tanC = \frac{b}{a} × \frac{c}{b} ( cancel b on numerator/ denominator )

                 = \frac{c}{a}

---------------------------------------------------------------------------

sinC = \frac{opposite}{hypotenuse} = \frac{AB}{BC} = \frac{c}{a}

tanB = \frac{opposite}{adjacent} = \frac{AC}{AB} = \frac{b}{c}

Thus

sinC tanB = \frac{c}{a} × \frac{b}{c} ( cancel c on numerator/ denominator )

                 = \frac{b}{a}

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Answer:

∠ RQS = 138°

Step-by-step explanation:

Since PR and PS are tangents to the circle, then

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Subtract the sum of the interior angles from 360° for ∠ RQS

∠ RQS = 360° - (90 + 90 + 42)° = 360° - 222° = 138°

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3 years ago
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Answer:

2^{2} + (2\sqrt{3}) ^{2} = 4 + 4 * 3 = 16 = 4^{2}

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The Pythagorean Theorem states that the two shorter sides of a right triangle squared and added together will equal the longest side (hypotenuse) of the right triangle squared. The longest side of this right triangle is 4, 4 squared is 16. The two shorter sides of the right triangle are 2 and 2\sqrt{3}, squared individually would be 4 and 12, and added together they also equal 16. These sides are a valid input for the Pythagorean Theorem, so these three sides are the sides of a right triangle. 2 and 2\sqrt{3} being the legs of the right triangle, and 4 being the hypotenuse.

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2. Solve the system of equations using the substitution method.
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Answer:

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Step-by-step explanation:

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