Question

Anyone know how to do 5c???? Please help!!!!!

Answer 1

Answer:

71° F

Step-by-step explanation:

Consider the rational part of f(t)

$\frac{40t^3}{t^3+100}$  ( divide numerator and denominator by t³

= $\frac{40}{1+\frac{100}{t^3} }$

As t → infinity then $\frac{100}{t^3}$ → 0 , the expression simplifies to

$\frac{40}{1+0}$ = $\frac{40}{1}$ = 40

Thus after driving for a long time

f(t) = 31 + 40 = 71° F