All categories

2 years ago

3 . Which list of numbers is ordered from least to

Mathematics

1 answer:

mihalych1998 [28]2 years ago

6 0

Answer:

it’s C. 0.02,0.2.1/2, 2 1/2

You might be interested in

Given the function f(x) = - 4x + 2. Find the range using the domain.<br> D:{-1, 2}<br> R:{ , }

Svet_ta [14]

Answer:

R { - 6, 6 }

Step-by-step explanation:

To find the range substitute the values of x from the domain into f(x)

f(- 1) = - 4(- 1) + 2 = 4 + 2 = 6

f(2) = - 4(2) + 2 = - 8 + 2 = - 6

Range { - 6, 6 }

5 0

3 years ago

*High School problem not Middle School

devlian [24]

Should be c ? can you send me a picture please ? and it’s dice .

4 0

3 years ago

If a ray bisects an angle, each newly formed angle measures 90 degrees.

prohojiy [21]

Answer:

A) Sometimes

A ) Sometimes is the correct answer because b) always and c) never is not possible

it cannot be always measured 90 degrees

3 0

2 years ago

Read 2 more answers

Matt gave half of his books to the local library and kept the other half. His best friend gave him 3 more books. He now has 57 b

Pani-rosa [81]

He started with 108 books

5 0

3 years ago

Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x

iren [92.7K]

Answer:

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

Step-by-step explanation:

One is asked to find the root of the following equation:

$2x^2+1=5x$

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

$ax^2+bx+c=0$

Change the given equation using inverse operations,

$2x^2+1=5x$

$2x^2-5x+1=0$

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

Simplify,

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

$\frac{5(+-)\sqrt{25-8}}{4}$

$\frac{5(+-)\sqrt{17}}{4}$

Rewrite,

$\frac{5(+-)\sqrt{17}}{4}$

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

8 0

2 years ago