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zheka24 [161]
3 years ago
10

3 . Which list of numbers is ordered from least to

Mathematics
1 answer:
mihalych1998 [28]3 years ago
6 0

Answer:

it’s C. 0.02,0.2.1/2, 2 1/2

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Due SOON!!
DedPeter [7]

Answer:

?=19

x=30

Step-by-step explanation:

5/6x - 1/5x = 19

5(5/6x) - 6(1/5x) = 19

25/30x-6/30x=19

19/30x=19

19x=19(30)

19x=570

x= 570/19

x=30

6 0
3 years ago
Find -11/15 if (n) =5n +6
Anestetic [448]
F(-11/5)=5(-11/5)+6
f(-11/5) = -11+6
<span>f(-11/5) = -5
Hope this helps!</span>
6 0
3 years ago
Can somebody help me with this?​
Ghella [55]

Answer:

x=11

Step-by-step explanation:

Since this is a 90º angle, 46º+(4x)º has to equal 90º, and you can make and solve an equation for this:

46+4x=90

4x=44

x=11

Check:

46+4x=90

46+4(11)=90

46+44=90

90=90

6 0
3 years ago
Select the correct product.<br><br> (y + z)3
Gre4nikov [31]

Answer:

3y + 3z

Step-by-step explanation:

(y + z)3

As the parenthesis contains 2 different variables, we cannot add them

Distribute (Multiply 3 by y and z)

3y + 3z

This is the simplest that this expression can get

Hope this helps :)

7 0
3 years ago
1. The table shows the probabilities of a response chocolate or vanilla when asking a child or adult. Use the formula for condit
Stels [109]
\begin{matrix}&\text{chocolate}&\text{vanilla}&\text{total}\\\text{children}&0.14&0.26&0.40\\\text{adults}&0.21&0.39&0.60\\\text{total}&0.35&0.65&1.00\end{matrix}

a. "Chocolate" and "Adults" (whatever those mean) will be independent as long as

P(\text{chocolate}\cap\text{adults})=P(\text{chocolate})\cdot P(\text{adults})

"Chocolate" has the marginal distribution given by the second column, with a total probability of P(\text{chocolate})=0.35. Similarly, "Adults" has the marginal distribution described by the third row, so that P(\text{adults})=0.60. Then

P(\text{chocolate})\cdot P(\text{adults})=0.35\cdot0.60=0.21

Meanwhile, the joint probability of "Chocolate" and "Adults" is given by the cell in the corresponding row/column, with P(\text{chocolate}\cap\text{adults})=0.21.

The probabilities match, so these events are indeed independent.

Parts (b) and (c) are checked similarly.

b. Yes;


P(\text{children})\cdot P(\text{chocolate})=0.40\cdot0.35=0.14
P(\text{children}\cap\text{chocolate})=0.14

c. Yes;

P(\text{vanilla})\cdot P(\text{children})=0.65\cdot0.40=0.26
P(\text{vanilla}\cap\text{children})=0.26
5 0
3 years ago
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