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2 years ago

3 . Which list of numbers is ordered from least to

Mathematics

1 answer:

mihalych1998 [28]2 years ago

6 0

Answer:

it’s C. 0.02,0.2.1/2, 2 1/2

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Three baby penguins and their father were sitting on an iceberg

Mrac [35]

Answer:

-4.2

Step-by-step explanation:

0.5 - 4.7= -4.2

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2 years ago

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Derive these identities using the addition or subtraction formulas for sine or cosine: sinacosb=(sin(a+b)+sin(a-b))/2

Sergeu [11.5K]

Answer:

The work is in the explanation.

Step-by-step explanation:

The sine addition identity is:

$\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b)$ .

The sine difference identity is:

$\sin(a-b)=\sin(a)\cos(b)-\cos(a)\sin(a)$ .

The cosine addition identity is:

$\cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b)$ .

The cosine difference identity is:

$\cos(a-b)=\cos(a)\cos(b)+\sin(a)\sin(b)$ .

We need to find a way to put some or all of these together to get:

$\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}$ .

So I do notice on the right hand side the $\sin(a+b)$ and the $\sin(a-b)$ .

Let's start there then.

There is a plus sign in between them so let's add those together:

$\sin(a+b)+\sin(a-b)$

$=[\sin(a+b)]+[\sin(a-b)]$

$=[\sin(a)\cos(b)+\cos(a)\sin(b)]+[\sin(a)\cos(b)-\cos(a)\sin(b)]$

There are two pairs of like terms. I will gather them together so you can see it more clearly:

$=[\sin(a)\cos(b)+\sin(a)\cos(b)]+[\cos(a)\sin(b)-\cos(a)\sin(b)]$

$=2\sin(a)\cos(b)+0$

$=2\sin(a)\cos(b)$

So this implies:

$\sin(a+b)+\sin(a-b)=2\sin(a)\cos(b)$

Divide both sides by 2:

$\frac{\sin(a+b)+\sin(a-b)}{2}=\sin(a)\cos(b)$

By the symmetric property we can write:

$\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}$

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2 years ago

What's the sum of 86.703 + 12.197

Ira Lisetskai [31]

98.9 thats what i got

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Simplify the folllowing: (xy^3 z^4)

allsm [11]

Answer:

Remove parentheses. xy³ z^4

4Step-by-step explanation:

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All swimming equipment is on sale with a 30% discount. A snorkeling set regularly sells

kupik [55]

Answer:

Step-by-step explanation:

50 * .30=15

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2 years ago