2 solutions.
Hope this helps!!
Consider the following table.
For this case, the first thing we should use is the following equation:
c (w) = 0.013w ^ 2-w-7
We note that w = 20 belongs to the interval [5, 30]. Therefore, we can use the equation.
Substituting w = 20 we have:
c (20) = 0.013 * (20) ^ 2- (20) -7
c (20) = - 21.8
Answer:
the wind chill temperature at 0f if the wind speed is 20 miles per hour is:
c (20) = - 21.8
Answer:
dont know if this is correct
Answer:
3x - 2y = 1
Step-by-step explanation:
Step 1: Find the slope
slope m = (y2 - y1)(/x2 - x1)
m = (4 - 1)/(3 - 1) = 3/2
Step 1: Use the formula y = mx + b to solve
This is slope-intercept form of a line. We have a slope of 3/2, and a point (x, y), which is (1, 1). Plug those values into the equation above and solve for b (the only variable we are missing
1 = (3/2)(1) + b
1 = 3/2 + b
1 - 3/2 = b
2/2 - 3/2 = b
-1/2 = b
Step 2: Rewrite the formula using the slope and the b value we just calculated
y = (3/2)x - 1/2
Step 3: Standard form of a line is ax + by = c, where a is a positive integer, so we rearrange the equation from step 2 to standard form.
y = (3/2)x - 1/2
-(3/2)x + y = -1/2 (subtract (3/2)x from both sides)
-3x + 2y = -1 (multiply by 2 to get rid of the fraction on x)
3x - 2y = 1 (multiply by -1 so a becomes positive)
