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4 years ago

What is the measure of BC? Need help ASAP!

Mathematics

1 answer:

Law Incorporation [45]4 years ago

3 0

Measure B to C is 48 unit

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miskamm [114]

Answer:

hardhard

Step-by-step explanation:

3 0

3 years ago

Solve the equation.<br> 1/2x+1/2x=x+1 <br><br> What is the solution?

Marizza181 [45]

Answer:

Since 0 ≠ 1, there are no solutions.

No solution

Step-by-step explanation:

7 0

4 years ago

Find m Someone pleaseee helpp

Alexus [3.1K]

Answer:

107°

Step-by-step explanation:

m∠m+m∠p= 180°

(7x+31)°(21x-19)°=180°

7x+31+21x-19= 180

7x+21x=180+19-31

28x=168

x= 168/28

x= 6

m∠p= (21x-19)°

= (21(16)-19)°=(126-19)°

= 107°

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hope it helps..

have a great day!!

8 0

3 years ago

BRAINLIEST:

Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

what you do is -4(2)^-2 which is -1

then you do 3(5)^0 which is 3

then you add it together and it is 2

7 0

3 years ago

70 POINTS!!!!!!!!!! Given: E, F, Q, D∈k(O),O ∈ ED, m∠DFQ = 10°, measure of arc EF = 28° Find: Angles of △EFQ

Likurg_2 [28]

Answer:

The measures of angles of triangle EFQ are

1) $m\angle EFQ=100\°$

2) $m\angle FEQ=66\°$

3) $m\angle EQF=14\°$

Step-by-step explanation:

step 1

Find the measure of arc QD

we know that

The inscribed angle is half that of the arc it comprises.

$m\angle DFQ=\frac{1}{2}(arc\ QD)$

substitute the given value

$10\°=\frac{1}{2}(arc\ QD)$

$20\°=(arc\ QD)$

$arc\ QD=20\°$

step 2

Find the measure of arc FQ

we know that

$arc\ QD+arc\ FQ+arc\ EF=180\°$ ---> because ED is a diameter (the diameter divide the circle into two equal parts)

substitute the given values

$20\°+arc\ FQ+28\°=180\°$

$arc\ FQ=180\°-48\°=132\°$

step 3

Find the measure of angle EFQ

we know that

The inscribed angle is half that of the arc it comprises.

$m\angle EFQ=\frac{1}{2}(arc\ QD+arc\ ED)$

substitute the given value

$m\angle EFQ=\frac{1}{2}(20\°+180\°)=100\°$

step 4

Find the measure of angle FEQ

we know that

The inscribed angle is half that of the arc it comprises.

$m\angle FEQ=\frac{1}{2}(arc\ FQ)$

substitute the given value

$m\angle FEQ=\frac{1}{2}(132\°)=66\°$

step 5

Find the measure of angle EQF

we know that

The inscribed angle is half that of the arc it comprises.

$m\angle EQF=\frac{1}{2}(arc\ EF)$

substitute the given value

$m\angle EQF=\frac{1}{2}(28\°)=14\°$

5 0

4 years ago