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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

Mathematics

1 answer:

topjm [15]3 years ago

5 0

Answer: B. neither

Step-by-step explanation:

A function is even when f(x) = f(-x).

A function is odd when f(-x) = -f(x).

f(x) = 2x³ - x²

f(-x) = 2(-x)³ - (-x)²

= -2x³ - x²

f(x) = 2x³ - x² ≠ f(-x) = -2x³ - x² so it is NOT EVEN

-f(x) = -(2x³ - x²)

= -2x³ + x²

f(-x) = -2x³ - x² ≠ -f(x)= -2x³ + x² so it is NOT ODD

Therefore, it is NEITHER even nor odd.

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3 years ago

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2 years ago

The Quadratic Formula, x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times

DedPeter [7]

Answer:

The correct option is 2 .

Therefore ,the missing denominator of the solution. 4 plus or minus the square root of 2, all over is  2 . 

$x=\dfrac{4\pm\sqrt{2}}{2}$

Step-by-step explanation:

For a Quadratic Equation ax² + bx + c = 0

By Formula Method we get

$x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

So we have Quadratic Equation is 2x² - 8x + 7 = 0

On Comparing we get

$a=2\\b=-8\\c=7$

Substituting a , b, c values we get

$x=\dfrac{-(-8)\pm\sqrt{(-8)^{2}-4(2)(7)}}{2(2)}\\\\x=\dfrac{8\pm\sqrt{64-56}}{4}\\\\x=\dfrac{8\pm\sqrt{8}}{4}\\\\x=\dfrac{8\pm2\sqrt{2}}{4}\\\\x=2(\dfrac{4\pm\sqrt{2}}{4})\\\\x=\dfrac{4\pm\sqrt{2}}{2}$

Therefore ,the missing denominator of the solution. 4 plus or minus the square root of 2, all over is  2 . 

7 0

3 years ago