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liq [111]
3 years ago
12

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

Mathematics
1 answer:
topjm [15]3 years ago
5 0

Answer:  B. neither

<u>Step-by-step explanation:</u>

A function is even when f(x) = f(-x).

A function is odd when f(-x) = -f(x).


f(x) = 2x³ - x²

f(-x) = 2(-x)³ - (-x)²

      = -2x³ - x²

f(x) = 2x³ - x²     ≠    f(-x) = -2x³ - x²     so it is NOT EVEN


-f(x) = -(2x³ - x²)

      = -2x³ + x²

f(-x) = -2x³ - x²     ≠    -f(x)= -2x³ + x²     so it is NOT ODD  


Therefore, it is NEITHER even nor odd.

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How does the point of intersection of the graphs represent the solution of a system of linear equations
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
2/3 of a number is 28 what is that number​
Sidana [21]

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28×3÷2=14×2×3÷2=14×3=42

8 0
3 years ago
When is a polynomial factored completely?
Jet001 [13]

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A polynomial is factored completely when nothing else in the expression can be factored

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x^2+3x-4 completely factored looks like (x+4)(x-1)

8 0
3 years ago
What is the value of the x variable in the solution to the following system of equations? (5 points) 2x − 3y = 3 5x − 4y = 4 Sel
Rama09 [41]

Answer:

D. There is no x value as there is no solution to this system

Step-by-step explanation:

2x − 3y = 3                                  5x − 4y = 4

5x - 4y = 4               -4y = -5x + 4                         y = 5/4x - 1

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2x - 15/4x + 3 = 3

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8 0
2 years ago
The Quadratic Formula, x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times
DedPeter [7]

Answer:

The correct option is  2 .

Therefore ,the missing denominator of the solution. 4 plus or minus the square root of 2, all over is <u>  2 . </u>

     x=\dfrac{4\pm\sqrt{2}}{2}

Step-by-step explanation:

For a Quadratic Equation ax² + bx + c = 0

By Formula Method we get

x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}

So we have Quadratic Equation is 2x² - 8x + 7 = 0

On Comparing we get

a=2\\b=-8\\c=7

Substituting a , b, c values we get

x=\dfrac{-(-8)\pm\sqrt{(-8)^{2}-4(2)(7)}}{2(2)}\\\\x=\dfrac{8\pm\sqrt{64-56}}{4}\\\\x=\dfrac{8\pm\sqrt{8}}{4}\\\\x=\dfrac{8\pm2\sqrt{2}}{4}\\\\x=2(\dfrac{4\pm\sqrt{2}}{4})\\\\x=\dfrac{4\pm\sqrt{2}}{2}

Therefore ,the missing denominator of the solution. 4 plus or minus the square root of 2, all over is <u>  2 . </u>      

7 0
3 years ago
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