Answer: Does not exist.
Step-by-step explanation:
Since, given function, f(x) = 6x tan x, where −π/2 < x < π/2.
⇒ f(x) = 
And, for vertical asymptote, cosx= 0
⇒ x = π/2 + nπ where n is any integer.
But, for any n x is does not exist in the interval ( -π/2, π/2)
Therefore, vertical asymptote of f(x) where −π/2 < x < π/2 does not exist.
G/f(x) = x^2 - 6 / 3x + 1
3x + 1 = x^2 - 6
x^2 - 3x - 6 - 1 = 0
x^2 - 3x - 7 = 0
x = 4.54 , x = - 1.54
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Answer:
8064
Step-by-step explanation:
14 x 12= 168
168 x 48= 8064
Answer:
-2x² - 8x - 15
Step-by-step explanation:
-(2x² + 4x + 11) + (-4)
-2x² - 8x - 11 - 4
-2x² - 8x - 15