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Volgvan
3 years ago
5

What is the slope of the line that goes through (2,6) and (4,5)

Mathematics
1 answer:
Lesechka [4]3 years ago
3 0

Answer:

-1/2

Step-by-step explanation:

You find the change in the y coordinates. 6 -> 5 is -1. Now the same for the x. 2 -> 4 is +2. now place them in a fraction with the y/x -1/2. if both were negative then you would just cancel out the negatives.

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Help me please!!°-°​
masya89 [10]
It was complicated but I did it

4 0
3 years ago
Factorise the following:<br><img src="https://tex.z-dn.net/?f=%7B3x%7D%5E%7B2%7D%20%20%2B%205x%20-%2012" id="TexFormula1" title=
Fed [463]

Answer:

(x + 3)(3x - 4)

Step-by-step explanation:

Given

3x² + 5x - 12

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 12 = - 36 and sum = + 5

The factors are + 9 and - 4

Use these factors to split the x- term

3x² + 9x - 4x - 12 ( factor first/second and third/fourth terms )

= 3x(x + 3) - 4(x + 3) ← factor out (x + 3) from each term

= (x + 3)(3x - 4)

Thus

3x² + 5x - 12 = (x + 3)(3x - 4) ← in factored form

6 0
3 years ago
How do i solve 3x² - 8x + 2 = 0 using quadratic formula?
DENIUS [597]
3x^2 - 8x + 2 = 0\\ \\a=3 , \ \ b=-8 , \ \ c=2 \\ \\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a} =\frac{8-\sqrt{ (-8)^2-4 \cdot 3\cdot 2}}{2 \cdot 3} =\frac{8-\sqrt{ 64-24 }}{6} =\\ \\ =\frac{8-\sqrt{40 }}{6} = \frac{ 8-\sqrt{4\cdot 10 } }{6} = \frac{ 8-2\sqrt{ 10 }}{6} = \frac{2 (4-\sqrt{ 10 })}{6} = \frac{ 4-\sqrt{ 10 } }{3}

x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a} =\frac{8+\sqrt{ (-8)^2-4 \cdot 3\cdot 2}}{2 \cdot 3} = \frac{ 4+\sqrt{ 10 } }{3}



7 0
2 years ago
Read 2 more answers
Find the area of the figure shown. Use 3.14 to approximate pi
Nina [5.8K]
Alrighty

we gots 1/4 circle and paralellogram

area circle=pi times radius^2
area paralelogram=base times height


1/4 circle is
radius is 10 so
area part circle is 1/4 times pi times 10^2=100/4pi=25pi=78.5 m²

area paralllogram is
10 times 3 because 3 is height and 10 is base length or 30

30+78.5=108.5 m² is the area
4 0
3 years ago
Use integration by parts to find the integrals in Exercise.<br> ∫(4x-12)e-8x dx.
stepladder [879]

Answer:

e(2x^{2} -12x)-4x^{2}+C

Step-by-step explanation:

We have been given an indefinite integral as \int \left(4x-12\right)e-8x\:dx. We are asked to find the given integral.

Let us solve our given problem.

\int \left(4x-12\right)e\:dx-\int 8x\:dx

Take out constant:

e\int \left(4x-12\right)\:dx-8\int x\:dx

e(\int 4x\:dx -\int 12\right\:dx)-8\int x\:dx

e(\frac{4x^{1+1}}{2} -12x)-8*\frac{x^{1+1}}{1+1}+C

e(\frac{4x^{2}}{2} -12x)-8*\frac{x^{2}}{2}+C

e(2x^{2} -12x)-4x^{2}+C

Therefore, our required integral would be e(2x^{2} -12x)-4x^{2}+C.

5 0
2 years ago
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