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Nikitich [7]
3 years ago
14

Find te range, medían, and mode

Mathematics
2 answers:
Oliga [24]3 years ago
7 0

Answer:

mean the sum of a set of data divided by the number of items in the set

median the middle value of a set of data arranged in numerical order

range the difference between the largest and smallest data points

sveticcg [70]3 years ago
4 0
Range: The highest/biggest number subtracting the smallest number

Median: The middle number - put all the numbers in a numerical order (from smallest to the largest), and then find the number in the middle 

Mode: The most common number 

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Create an equivalent ratio to 10:16 by dividing both sides by 2. What is the equivalent ratio?
Darya [45]

10 / 2 = 5

16 / 2 = 8

The equivalent ratio is 5:8

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Sandra is 4 feet tall.Pablo is 10% talker than Sandra,and Michaela is 8% taller than Pablo.Explain how to Michaelas height with
Pavlova-9 [17]

Answer:

For Pablo's height, just make 10% of 4 a decimal which is .4 and add 4 to it. and then for Michaela do the same which is .8 and add 4 to it  so 5ft for Michaela

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3 years ago
If x2 = 30. what is the value of x? ​
kirza4 [7]

Answer:

5.4772255750516 that's if it is x squared

4 0
3 years ago
The Sun is v kilometers from the upper edge of the Earth's atmosphere and q kilometers from the surface of the Earth. Which of t
horsena [70]
The distance between the Earth's surface and the upper edge of the Earth's atmosphere would be Q - V.

The distance from the Sun to the Earth is Q. The distance from the Sun to the upper edge of the atmosphere is V. If you subtract V from Q, the remaining distance is that of the Earth's atmosphere.  Q - V = the atmosphere
6 0
2 years ago
Read 2 more answers
Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0
2 years ago
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