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3 years ago

(6.6 × 10⁰) + (7.8 × 10²)

Mathematics

2 answers:

Lorico [155]3 years ago

5 0

Answer:

786.6

Step-by-step explanation:

Anything to the ^0 is 1 so its 1 x 6.6 + 100 x 7.8

6.6 + 780

786.6

Alex73 [517]3 years ago

3 0

Answer:

786.6

Step-by-step explanation:

Problem:

(6.6 × 10⁰) + (7.8 × 10²)

Step 1 - Parenthesis:

(6.6 × 10⁰) + (7.8 × 10²)

Step 2 - Exponents(Left to Right):

(6.6 × 10^0) + (7.8 × 10^2) = (6.6 × 1) + (7.8 × 100)

Step 3 - Multiply(Left to Right):

(6.6 × 1) + (7.8 × 100) = 6.6 + 780

Step 4 - Add(Left to Right)

6.6 + 780 = 786.6

Step 5 - Answer:

786.6

<h3><u><em>Remember:</em></u></h3>

Parenthesis

Exponents(Left to Right)

Multiplication(Left to Right)

Division(Left to Right)

Addition(Left to Right)

Subtraction(Left to Right)

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A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confid

katrin [286]

Answer:

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 865, \pi = \frac{408}{865} = 0.4717$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 - 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.4384$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 + 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.5050$

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

6 0

2 years ago

6 family members share 1/4 of a of chocolate fudge what fraction of a pound does each family member get if they share equally .

photoshop1234 [79]

Answer:

The answer is 1/10

Step-by-step explanation:

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2 years ago

The angle θ1\theta_1 θ 1 theta, start subscript, 1, end subscript is located in Quadrant II\text{II} II start text, I, I, end

melomori [17]

Answer:

$\dfrac{3\sqrt{13}}{11}$

Step-by-step explanation:

Given that the angle $\theta_1$ is located in Quadrant II; and

$\cos(\theta_1)=-\dfrac{2}{11}$

In Quadrant II, x is negative and y is positive.

$\cos(\theta)=\dfrac{Adjacent}{Hypotenuse},\sin(\theta)=\dfrac{Opposite}{Hypotenuse}\\$Adjacent=-2\\Hypotenuse=11\\$

To find $\sin(\theta_1)$ , we first determine the opposite angle of $\theta_1$ .

This will be done using the Pythagoras theorem.

$Hypotenuse^2=Opposite^2+Adjacent^2\\11^2=Opposite^2+(-2)^2\\Opposite^2=121-4=117\\Opposite=\sqrt{117}=3\sqrt{13}$

Therefore:

$\sin(\theta_1)=\dfrac{Opposite}{Hypotenuse}=\dfrac{3\sqrt{13}}{11}$

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2 years ago

Which of the following could be the sum of exactly three consecutive integers?

Alexeev081 [22]

198 is your answer:

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2 years ago

The Arc Electronic Company had an income of 59 million dollars last year. Suppose the mean income of firms in the same industry

Zolol [24]

Answer:

0.0228 = 2.28% probability that a randomly selected firm will earn more than Arc did last year

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Suppose the mean income of firms in the same industry as Arc for a year is 45 million dollars with a standard deviation of 7 million dollars

This means that $\mu = 45, \sigma = 7$

What is the probability that a randomly selected firm will earn more than Arc did last year?

Arc earned 59 million, so this is 1 subtracted by the pvalue of Z when X = 59.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{59 - 45}{7}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that a randomly selected firm will earn more than Arc did last year

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2 years ago

(6.6 × 10⁰) + (7.8 × 10²)​

(6.6 × 10⁰) + (7.8 × 10²)