Answer:
17 lb I guess 8 don't think the question is full
Step-by-step explanation:
the question is half
You had the right idea using the Pythagorean theorem to solve for b.
Problem is for that triangle to work, the 5 and the 2√2 would have to switch places. The length of a leg cannot be larger than the length of the hypotenuse for it to truly be a right triangle.
Pythagorean theorem only works for the right triangles. Only way to "solve this problem would be to bring in complex numbers.
5² + b² = (2√2)²
25 + b² = 2²(√2)²
25 + b² = 4(2)
25 + b² = 8
b² = 8 - 25
b² = - 17
b = √-17
b= (√17i)
Then the problem with THIS is a measurement/distance cannot be negative... which goes against exactly what that complex number i is.
Answer:
Answer in simplified form is - 10 1/2 .
Step-by-step explanation:
We have given,
(5 1/4) ÷ (- 2 1/2)
This can be simplified as :
(5 1/4) ÷ ( -2 1/2)
Since 5 1/4 = 21/4 and -2 1/ 2 = -5/2
So we can write,
(5 1/4) ÷ ( -2 1/2) = 21/4 ÷ ( - 5/2)
or (21/4) / (-5/2)
or ( 21/4) * (-2/5)
or -42/20
or -21/10
or - 10 1/2 , this is the answer
Hence we get answer in simplified form as -10 1/2
Answer:
Tangent line states that a line in the plane of a circle that intersect the circle in exactly one point.
Common external tangent states that a common tangent that does not intersects the line segment joining the centers of circle.
Common internal tangent states that a common tangent that intersects the line segment joining the centers of circle.
Circumscribe polygon states that a polygon with all sides tangent to a circle contained within the polygon.
Therefore:
A polygon with all sides tangent to a circle contained within the polygon = Circumscribe polygon
A common tangent that intersects the line segment joining the centers of circle = Common internal tangent
A common tangent that does not intersects the line segment joining the centers of circle = Common external tangent
a line in the plane of a circle that intersect the circle in exactly one point = Tangent line
<h2><u>abcd kids</u></h2>
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