Let ‘n’ be the middle term of three consecutive even integers. Therefore, (n) is also an even number. Hence, the even number preceding it will be (n - 2) and the even number after it will be (n + 2), since we need consecutive even integers.
Hence, we have (n - 2), (n), (n + 2).
Sum of the Integers :- = (n - 2) + (n) + (n + 2) = n - 2 + n + n + 2 = n + n + n + 2 - 2 = n + n + n => 3n
