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masha68 [24]
3 years ago
14

Mr. Dorado has completed 75% of his morning run. Which of the following sets does not represent 75%?

Mathematics
1 answer:
Dovator [93]3 years ago
8 0

Answer:

Step-by-step explanation:

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7 and2/3 - 5and 5/8=
dolphi86 [110]

7 2/3 - 5 5/8 = 7 16/24 - 5 15/24 = 2 1/24
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3 years ago
Help pls!
4vir4ik [10]

Answer:

the probability that the next gumball that comes out will be neither yellow nor blue = 6/17

Step-by-step explanation:

neither yellow nor blue gumball = pink gumball = 6

3 yellow + 8 blue + 6 pink = total =17

3 0
3 years ago
L need help with this​
soldi70 [24.7K]

Answer:

$24.11

Step-by-step explanation:

Let the cost of the present be c.

Then (3/4)c = $18.33.

To isolate (solve for) c, mult. both sides of this equation by (4/3):

(4/3)(3/4)c = (4/3)($18.33), or

             c  =  $24.11

5 0
3 years ago
Find the values of b <br>b²= 256<br>b=?​
ehidna [41]

Answer:

if b²=256

then b=16

....................

5 0
3 years ago
Read 2 more answers
Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.
NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}  (1)

furthermore, you know that:

\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}

lets call to this integral, the integral Io.

for a general form of I you have In:

I_n=\int_0^{\infty}x^ne^{-ax^2}dx

furthermore you use the fact that:

I_n=-\frac{\partial I_{n-2}}{\partial a}

by using this last expression in an iterative way you obtain the following:

\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}} (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}

5 0
3 years ago
Read 2 more answers
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