What is the slope of a line perpendicular to the line whose equation is 12x-9y=135
1 answer:
Answer:
Step-by-step explanation:
First, we need to isolate y.
1. Subtract 12x from both sides.
-9y=-12x+135
2. Divide by -9 in order to isolate y.
3. Understand that perpendicular equations' slopes are opposite and reciprocal to the original equation. The slope of the original equation is , so the reciprocal and opposite (flip and change the sign) slope would be
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Answer:
D
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Calculate the slope of the given line using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 2, - 4) and (x₂, y₂ ) = (2, 2) ← 2 points on the line
m = =
=
Parallel lines have equal slopes and using (a, b) = (- 3, 1), then
y - 1 = (x - (- 3)), that is
y - 1 = (x + 3) ← in point- slope form