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schepotkina [342]
3 years ago
10

What is the slope of a line perpendicular to the line whose equation is 12x-9y=135

Mathematics
1 answer:
trasher [3.6K]3 years ago
7 0

Answer:

\frac{-9}{12}

Step-by-step explanation:

First, we need to isolate y.

1. Subtract 12x from both sides.

-9y=-12x+135

2. Divide by -9 in order to isolate y.

y=\frac{12}{9} x-15

3. Understand that perpendicular equations' slopes are opposite and reciprocal to the original equation. The slope of the original equation is \frac{12}{9}, so the reciprocal and opposite (flip and change the sign) slope would be \frac{-9}{12}.

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Answer:

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Step-by-step explanation:

The initial position was (0,0,0) since it was the origin

Now, we have a movement of positive x at a distance of 4 units, with a distance of z a total of 7 units(negative since downward)

The current position is thus;

(4,0,-7)

Thus correlates to (x,y,z) and our y has remained zero as there is no movement along the y-axis

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(n + 12) x 5 + 7n Need equivalent expression
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Answer:

12n + 60

General Formulas and Concepts:

<u>Pre-Algebra</u>

Distributive Property

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

(n + 12) × 5 + 7n

<u>Step 2: Simplify</u>

  1. Distribute 5:                     5(n) + 5(12) + 7n
  2. Multiply:                            5n + 60 + 7n
  3. Combine like terms:        12n + 60
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Step-by-step explanation:

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