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schepotkina [342]
3 years ago
10

What is the slope of a line perpendicular to the line whose equation is 12x-9y=135

Mathematics
1 answer:
trasher [3.6K]3 years ago
7 0

Answer:

\frac{-9}{12}

Step-by-step explanation:

First, we need to isolate y.

1. Subtract 12x from both sides.

-9y=-12x+135

2. Divide by -9 in order to isolate y.

y=\frac{12}{9} x-15

3. Understand that perpendicular equations' slopes are opposite and reciprocal to the original equation. The slope of the original equation is \frac{12}{9}, so the reciprocal and opposite (flip and change the sign) slope would be \frac{-9}{12}.

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Find the next two terms in the given sequence, then write it in recursive form. A.) {7,12,17,22,27,...} B.) { 3,7,15,31,63,...}​
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Answer:

A) a_n = 5n + 2

B) a_n = (2^(n + 1)) - 1

Step-by-step explanation:

A) The sequence is given as;

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The differences are:

5,5,5,5.

This is an arithmetic sequence following the formula;

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Thus;

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Now, a_1 = 7. Thus;

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B) The sequence is given as;

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Now, let's write out the differences of this sequence:

Differences are:

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This shows that it is a geometric sequence with a common ratio of 2.

In the given sequence, a_1 = 3 and a_2 = 7 and a_3 = 15

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Also, a_(2 + 1) = 2a_2 + 1

Combining both equations, we can deduce that: a_(n + 1) = 2a_n + 1

Thus; a_n can be expressed as:

a_n = (2^(n + 1)) - 1

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Step-by-step explanation:

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