The graph of a linear equation contains the points (3,11) and (-2,1) . Which point also lies on the graph.

Use the drawing tools to form the correct answer on the grid.

Rus_ich [418]

Answer:

Here is the answer I got when I graphed the equation I got it correct so here it is: Hope this Helps!!!

Step-by-step explanation:

Draw a line exactly from 120 to the top of number 9 on the x axis labeled # of Books

PLEASE GIVE BRAINLIEST IF THIS HELPED!!!

THANKS!!!

7 0

3 years ago

Find the mode of the following list of points earned on a 16 point quiz given during a finance class.

koban [17]

Answer:

7

Step-by-step explanation:

The mode is the most repeated number in the data set. In this case, that is 7 because it's repeated 3 times.

8 0

3 years ago

Read 2 more answers

Use a paragraph, flow chart, or two-column proof to prove the angle congruency. Given: ∠ CXY ≅ ∠ BXY

Llana [10]

Answer:

See explanation

Step-by-step explanation:

Consider triangles CAX and BAX. In these triangles,

$\overline{AC}\cong \overline{AB}$ - given
$\angle CAX\cong \angle BAX$ - given
$\overline{AX}\cong \overline{AX}$ - reflexive property

By SAS postulate, $\triangle CAX\cong \triangle BAX$

Congruent triangles have conruent corresponding parts. So,

$\overline{CX}\cong \overline{BX}$

Consider triangles CXY and BXY. In these triangles,

$\overline{CX}\cong \overline{BX}$ - proven
$\angle CXY\cong \angle BXY$ - given
$\overline{XY}\cong \overline{XY}$ - reflexive property

By SAS postulate, $\triangle CXY\cong \triangle BXY$

Congruent triangles have conruent corresponding parts. So,

$\angle XCY\cong \angle XBY$

5 0

3 years ago

Can someone pls help

MakcuM [25]

when x =1 , y = 3

when x = 3, y =27

27-3 = 24

3-1 = 2

24/2 = 12

rate of change = 12

3 0

3 years ago

QUESTION 1 The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards.Assume that the driving

GarryVolchara [31]

Answer:

$P(X>300)$

And we can find this probability with the complement rule:

$P(X>300)= 1-P(X$

Step-by-step explanation:

For this case we define the random variable X ="driving distance for the top 100 golfers on the PGA tour" and we know that:

$X \sim Unif (a=284.7, b=310.6)$

And for this case the probability density function is given by:

$f(x) =\frac{1}{310.6 -284.7} =0.0386 , 284.7 \leq X \leq 310.6$

And the cumulative distribution function is given by:

$F(x) =\frac{x-284.7}{310.6-284.7} , 284.7 \leq X \leq 310.6$

And we want to find this probability:

$P(X>300)$

And we can find this probability with the complement rule:

$P(X>300)= 1-P(X$

6 0

3 years ago