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Klio2033 [76]
3 years ago
6

Write a ratio to express the number of people who preferred WCLM

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0
Do it yourself dritos and mtn dew
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Find the value of x and simplify completely
kondaur [170]
The value would be more than c
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Jenny was planning a trip to the United Arab Emirates. Before going, she did some research and learned that the exchange rate is
Blizzard [7]
4 dirhams is equal to 1 dollar so if you were to multiply each by 5 you would have 20 dirhams equaling 5 dollars
5 0
3 years ago
The coordinates of the vertices of right triangle SUE are S(6, 0), U(0, 8), and E(0, 0). What are the coordinates of the midpoin
Irina-Kira [14]
SE is hypotenuse so with having <span>coordinates of S and E we can say midpoint is (6+0/2,8+0/2)=(3,4)
i really don't know what are those options </span>
3 0
3 years ago
Find the area of a circle circumscribing an equilateral triangle of side 15cm.<br> Take pi = 3.14.
miskamm [114]

Answer:

236 cm²

Step-by-step explanation:

Height of an equilateral triangle (h) = √3 /2 (l)

l = side of the equilateral triangle.

h = √3 /2 (15)

In an equilateral triangle the orthocenter, centroid, circumcenter and incenter are in the same spot

The center of the circle is the centroid and height match  with the median. The radius of the circumcircle is equal to two thirds the height.

Formula for the Radius of the circumcircle = 2/3 h

= 2/3 x √3 /2 (15)

= 5 √3 cm     (=radius)

Area of the circle = πr^

= 3.14 x( 5 √3 ) ^

=3.14 x(25*3)

=3.14 x 75

=235.5

=236 cm²

8 0
3 years ago
Which is not an equation of the line going through (6, 7) and (2, –1)?
garri49 [273]
Answer - D.

you basically find the equation of the line first and eliminate the wrong answers...

Strategy:  before u do any of this, label your coordinates as (X1,Y1) and (X2,Y2) and u can choose any of ur points to be as x1 or x2 or y1 or y1...
basically, I'll choose (6,7) as (x1,y1) and (2,-1) as (x2,y2). SO,

First you have to  find the gradient (m) of the line.
  you do this by using the formula m = Y2-Y1 / X2-X1 (where '/' is division sign) ....
Put the numbers in their respective places and your gradient will be 2x. we put the x after our number to represent it as a gradient as the straight line formula is y = mx+c and you've found the m.
NOW.
use the formula Y-Y1=m(x-x1) to find the equation of the line.Again u can use any Y1 and X1 here but remember your m is 2

replace the digits and solve...Hopefully you'll get sth like this if you use the points (6,7):
Y-7 = 2(x-6) ....
y=2x-12+7...
Y=2x-5! <<<< this is your straight line equation!
Now all u gotta do is rearrange all your options into y = mx+c.
D. is incorrect as it gives us y=2x+5 and not y = 2x-5 unlike the others 
 

Hope you get it!




7 0
3 years ago
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