Answer:
about 0.177 mg/mL
Step-by-step explanation:
The maximum is found where the derivative of C(t) is zero.
dC/dt = 1.35e^(-2.802t) -(1.35t)2.802e^(-2.802t) = 0
Solving for t gives ...
t = 1/2.802
So, the maximum C(t) is ...
C(1/2.802) = 1.35/2.802e^(-1) ≈ 0.177 . . . . . mg/mL
The maximum average BAC during the first 6 hours is about 0.177 mg/mL.
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The maximum occurs about 21 minutes 25 seconds after consumption.
I don't know if you have to do this on a graph, or just on a blank space. But, noncollinear means, "not on the same line". So, if you were to draw four points in a blank spot on a piece of paper, just draw four points in random places, making sure they aren't all directly in line with eachother. For a graph, use points like: (-6,2), (5,7), (8,3), and (1,-3). Notice that none of them have the same x or y coordinates, so they can't possibly be collinear.
I think the better buy is the 1.50 for 5oz
C. 343 because <span>A perfect cube is the result of multiplying a number </span>three<span> times by itself.
1, 8, 27, 64, 125, 216, 343, and so on
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