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hram777 [196]
3 years ago
6

Using the least common denominator rename 3/5 and 1/20

Mathematics
2 answers:
irina1246 [14]3 years ago
6 0

Answer:

12/20 and 1/20.

Step-by-step explanation:

The least common denomiator between 3/5 and 1/20 is 20.

For the first equation, we multiply the numerator and denominator by 4 to get 12/20.

The second equation's denominator is already 1/20, so we can leave it as is.

The final answer is 12/20 and 1/20.

UkoKoshka [18]3 years ago
5 0
LCD is 20
3/5 -> 12/20
1/20 -> 1/20
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Explore sums of complex
Charra [1.4K]

The two-point A and B will be -1+2i and -2+2i respectively.

<h3>What is the complex number?</h3>

A complex number is one that has both a real and an imaginary component, both of which are preceded by the letter I which stands for the square root of -1.

The complex number is given as;

x+iy

Where x is the real part and iy is the imaginary part.

The two points added to obtained -3 + 4i are;

A = -1+2i

B= -2+2i

The sum of the two points is;

⇒A+B;

⇒-1+2i + -2+2 i

⇒-3 + 4 i

Hence the two-point A and B will be -1+2i and -2+2i respectively.

To learn more about the complex number, refer to the link;

brainly.com/question/10251853

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8 0
2 years ago
Here are the costs of the sametypes is shops shop a pack 4 batteries £1.60 shop b pack of 6 batteries £2.70
noname [10]

Answer:

Shop a

Step-by-step explanation:

1.60/4=£0.4 per battery

2.7/6= £0.45 per battery

Hence the batteries at shop a are cheaper

6 0
3 years ago
140,250 to the nearest hundred thousan
abruzzese [7]
140,000. the hundred is under 5 so you round down
8 0
3 years ago
Read 2 more answers
10 to the 3rd power + nine+ 1 to the 3rd power
Svetlanka [38]
I don’t understand this can you explain please
4 0
3 years ago
Solve the system of equations y = 40x2 and y = 19x + 3 algebraically.
ikadub [295]

We have been given a system of nonlinear equations.

\\y=40x^{2},y=19x+3

In order to solve this system we can first equate the two equations in order to get a quadratic in x.

\\40x^{2}=19x+3

Our next step is to bring all the terms on one side.

\\40x^{2}-19x-3=0

Now we have to solve this equation. We can solve it by factoring using the splitting middle term method.

\\40x^{2}-24x+5x-3=0

\\8x(5x-3)+(5x-3)=0

\\(8x+1)(5x-3)=0

Upon setting each of these factors equal to zero using zero product property we get

\\8x+1=0 \text{ or } 5x-3 = 0

Upon solving both these equations we get

\\x=-\frac{1}{8} \text{ or } x=\frac{3}{5}

Now we can substitute these values of x in the equation

y=19x+3

We get

\text{For }x=- \frac{1}{8} \Rightarrow y=19(- \frac{1}{8})+3= \frac{5}{8}\\

\text{For }x= \frac{3}{5}\Rightarrow y=19( \frac{3}{5})+3= \frac{72}{5}\\

Therefore, our final set of solutions are

(x,y)=(- \frac{1}{8},\frac{5}{8}) \text{ and } ( \frac{3}{5}, \frac{72}{5})


6 0
3 years ago
Read 2 more answers
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